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AlexFokin [52]
3 years ago
14

Why do atmoic numbers increase from left to right across any given row of the periodic table

Chemistry
1 answer:
stira [4]3 years ago
4 0
They have increased number of protons which is the atomic number. 
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A flashbulb of volume 2.70 mL contains O2(g) at a pressure of 2.30 atm and a temperature of 30.0 °C. How many grams of O2(g) doe
Sholpan [36]
P = 2.30 atm

Volume in liter = 2.70 mL / 1000 => 0.0027 L

Temperature in K = 30.0 + 273 => 303 K

R = 0.082 atm

molar mass O2 = 31.9988 g/mol

number of moles O2 :

P * V = n * R* T

2.30 * 0.0027 = n * 0.082 * 303

0.00621 = n * 24.846

n = 0.00621 / 24.846

n = 0.0002499 moles of O2

Mass of O2:

n = m / mm

0.0002499 = m / 31.9988

m = 0.0002499 * 31.9988

m = 0.008 g
3 0
3 years ago
Nombra cada uno de los siguientes hidrocarburos de acuerdo a las reglas de la IUPAC
myrzilka [38]

Answer:

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

Explanation:

Toda la idea de la nomenclatura IUPAC es permitir que la estructura de la sustancia se derive de su nombre y viceversa.

La nomenclatura IUPAC es un sistema universalmente aceptado para nombrar compuestos químicos.

los nombres de los compuestos enumerados son;

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

3 0
2 years ago
Name the organic compound of ch3chohch2ch3
snow_lady [41]

Answer:

Flavouring agent 2-Butanol, or sec-butanol, is an organic compound with formula CH3CH(OH)CH2CH3.

4 0
2 years ago
A photon of light possesses 5 x 10^-19 J of energy. Calculate its frequency
saveliy_v [14]

Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

4 0
3 years ago
Help please it’s confusing to me
Colt1911 [192]

Answer:

B, H, E, G, C, D, A, F

Explanation:

The ones closest to the bottom are the oldest

6 0
2 years ago
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