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Dmitry_Shevchenko [17]
2 years ago
12

Read the chemical equation. n2 3h2 → 2nh3 using the volume ratio, determine how many liters of nh3 is produced if 1.2 liters of

h2 reacts with an excess of n2, if all measurements are taken at the same temperature and pressure?
Chemistry
1 answer:
irina [24]2 years ago
3 0

0.8 liters of NH₃ is produced.

<h3 /><h3>What is Chemical equation?</h3>

A chemical equation is a symbolic representation of a chemical reaction in the form of symbols and formulae, where the reactant entities are given on the left and the product entities are given on the right, with a plus sign separating the entities in both the reactants and the products and an arrow pointing in the direction of the products to indicate the reaction's direction. The absolute values of the stoichiometric numbers are shown as coefficients next to the symbols and formulas of the entities. Jean Beguin drew the first chemical equation in 1615.

pressure - The SI unit for pressure is the pascal (Pa), which is equal to one newton per square metre (N/m2) of force per unit area of surface. An object's pressure is inversely proportional to the area it is pressing on and inversely proportional to the force it applies.

Given chemical reaction is:

N₂ + 3H₂ → 2NH₃

From the stoichiometry of the reaction, it is clear that:

3 liters of H₂ = produce 2 liters of NH₃

1.2 liters of H₂ = produce 2/3 × 1.2 = 0.8 liters of NH₃

to learn more about chemical reaction go to - brainly.com/question/11231920

#SPJ4

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Answer:

Carbon dioxide is a gas at room temperature

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A student was asked to determine the concentration of ammonia, a volatile substance used in the clinical setting as a respiretor
UNO [17]

This question is describing two chemical equations whereby the concentration of ammonia has to be determined. The first reaction is between 25.00 mL of ammonia and 50.00 mL of 0.100-M HCl whose excess was neutralized with 21.50 mL of 0.050-M Na₂CO₃ and thus, the concentration ammonia in the cloudy solution was determined as 0.114 M.

First of all we need to go over the titration of the excess HCl with Na₂CO₃ by writing the chemical equation it takes place when they react:

2HCl+Na_2CO_3\rightarrow 2NaCl+CO_2+H_2O

Whereas the mole ratio of HCl to Na₂CO₃ is 2:1 and the volume of the HCl leftover is determined as follows:

V_{HCl}^{leftover}=\frac{2*0.050M*21.50mL}{0.100M} =21.5mL

Next, we infer that the consumed volume of HCl by the ammonia solution was:

V_{HCl}^{consumed}=50.00mL-21.50mL=28.5 mL

Then, we write the chemical equation that takes place between ammonia and HCl:

HCl+NH_3\rightarrow NH_4Cl

Whereas the mole ratio is now 1:1, which means that the concentration of ammonia was:

M_{NH_3}=\frac{28.5mL*0.100M}{25.00mL}\\\\ M_{NH_3}=0.114M

Learn more:

  • (Titration) brainly.com/question/15687419
  • (Titration) brainly.com/question/25328286
8 0
2 years ago
How are ionic compounds named?
telo118 [61]

Answer:

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions. For binary ionic compounds (ionic compounds that contain only two types of elements), the compounds are named by writing the name of the cation first followed by the name of the anion.

Explanation:

Hope this helps.

3 0
3 years ago
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region o
Llana [10]

Answer:

5.75

Explanation:

Weak acid and strong base,

Make it a two part problem

The first will be Partial neutralization of the weak acid, while the second is the equilibrium and final pH

1.Parameters

HC2H3O2 =10mL x 0.75M = 7.5 mmol

NaOH =22mL x 0.30M = 6.6 mmol

R HC2H3O2 + OH- --> C2H3O2- + H2O

I 7.5 mmol 6.6 mmol 0 mmol ignore

C -6.6 mmol -6.6 mmol +6.6 mmol

E 0.9 mmol 0.0 mmol 6.6 mmol

2.) HC2H3O2 --> H+ + C2H3O2-

Initial concentrations

[HC2H3O2]: 0.9 mmol / 32mL = 0.0281M

[H+]:

[C2H3O2-]: 6.6 mmol x 32mL = 0.206M

Concentrations at equilibrium

[HC2H3O2]: 0.0281M - x

[H+]: [C2H3O2-]: 0.206M + x

If x is small and can be ignored except [H+]

Substitute and solve

1.3 x 10-5 = (x)(0.206)

(0.0281)

X= 1.77 x 10-6M => pH = 5.75

3 0
3 years ago
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