An ideal monatomic gas initially has a temperature of 330 K and a pressure of 6.00 atm. It is to expand from volume 500 cm3 to v
1 answer:
You might be interested in
Answer:
Velocity of golf ball≅ 12.87mph
Explanation:
Using the theory of conservative momentum to both the club head and the golf ball we have;
Qi1 + Qi2= Qf1 + Qf2
Qi1: initial momentum for the club head
Qf1: final momentum for the club head
Qi2: initial momentum for the golf ball
Qf2: final momentum for the golf ball
momentum (Q) = Mass x velocity
which means the sum of the momentums of both club head and golf ball has to be the same before and after they have collided.
using the Coeficient of restitution e= 0.83 allows us to know what kind of collision we are dealing with, which is a partially elastic collision since
0> e=0.83 >1.
Qi1= 190 x 94= 17,860 mph.g
Qf1= 190 x Vf1
Qi2= 46 x 0= 0 mph.g
Qf2= 46x Vf2
Using the value of e to determine Vf2 as the final velocity of the golf ball:
e=
0.83=
Vf1= (0.83 x 94)+ Vf2
Vf1= 78.02 + Vf2
Qi1 + Qi2= Qf1 + Qf2
17,860 + 0 = 190xVf1 + 46xVf2
17,860= 190x (78.02+Vf2) + 46xVf2
17,860= 14,823+ 190xVf2+46xVf2
Vf2≅ 12.87mph
Answer:
Explanation:
<u>Given:</u>
- Diameter of the plates of the capacitor, D = 21 cm = 0.21 m.
- Distance of separation between the plates, d = 1.0 cm = 0.01 m.
- Minimum value of electric field that produces spark,
When the dimensions of the plate of the capacitor is comparatively much larger than the distance of separation between the plates, then, according to the Gauss' law of electrostatics, the value of the electric field strength in the region between the plates of the capacitor is given by
where,
= surface charge density of the plate of the capacitor =
.
= magnitude of the charge on each of the plate.
= surface area of each of the plate =
= electrical permittivity of free space, having value =
For the minimum value of electric field that produces spark,
It is the maximum value of the magnitude of charge which can be added up to each of the plates of the capacitor.