a. Final pressure= 5atm
b. Work done = 5000 Joules
<h3>How to determine the parameters</h3>
Given;
- Temperature = 330K
- P1 = 6 atm
- V1 = 500cm^3
- V2 = 1500cm^2
In adiabatic expansion, temperature is constant
P1V1 = P2V2
Now, let's substitute the values into the formula
6 × 500 = 1500 P2
300 = 1500P2
Make 'p2' subject of formula
P2 = 1500/300
P2 = 5 atm
The formula for work done is given as:
Workndone = P ∆ volume
Work done = 5 × ( 1500 - 500)
Work done = 5 × 1000
Work done = 5000 Joules
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