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konstantin123 [22]

3 years ago

7

For what reason Do meteorogists use isobars on a weather map

2 answers:

sdas [7]3 years ago

7 0

Answer:

Isobars are similar to height lines on a geographical map, and they are drawn so that they can never cross each other. Meteorologists use isobars on weather maps to depict atmospheric pressure changes over an area and to make predictions concerning wind flow.

Explanation:

Airida [17]3 years ago

3 0

Answer:Isobars are similar to height lines on a geographical map, and they are drawn so that they can never cross each other.

Explanation:

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The SAF operates the M113 Ultra APC.

HACTEHA [7]

The volume of the object must be no larger than $11.15 m^3$ .

Explanation:

In order for an object to be able to float in water, its density must be equal or smaller than the water density.

The density of water is:

$\rho = 1000 kg/m^3$

This means that the density of the object must be no larger than this value.

We also know that the density of an object is given by

$\rho = \frac{m}{V}$

where

m is the mass of the object

V is its volume

For the object in this problem, the mass is

$m=1.115\cdot 10^4 kg$

Therefore, we can re-arrange the equation to find its volume:

$V=\frac{m}{\rho}=\frac{1.115\cdot 10^4}{1000}=11.15 m^3$

So, the volume of the object must be no larger than $11.15 m^3$ .

Learn more about density:

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8 0

3 years ago

Please help me<br> gqvebqubgk yfawcyvgkbuh

Sergeu [11.5K]

Answer:CCCCCCCCCCCCCCCCC

Explanation:CCCCCCCCCCCCC

4 0

3 years ago

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The joule (J) is a unit of energy. Recall that energy may be converted between many different forms such as mechanical energy, t

REY [17]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The workdone is $W = -177.275J$

Explanation:

From the question we are told that

The initial Volume is $Vi = 0.160 L$

The final volume is $V_f = 0.510L$

The external pressure is $P = 5.00 \ atm$

Generally the change in volume is

$\Delta V = V_f - V_i$

Substituting values we have

$\Delta V = 0.510 -0.160$

$= 0.350L$

Generally workdone is mathematically represented as

$W = -P \Delta V$

W is negative because the working is done on the environment by the system which is indicated by volume increase

Substituting values

$W = - 5* 0.350$

$= -1.75 \ L \ \cdot atm$

Now $1 \ L \cdot atm = 101.3J$

Therefore $W = -1.75* 101.3$

$= -177.275J$

7 0

3 years ago

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Looking at the bottom standing wave in the picture, how many complete waves are present?

Shtirlitz [24]

Answer:

the last one

Explanation:

4 0

2 years ago

Is the change in position of an object

natima [27]

Displacement is the change in position

6 0

4 years ago

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