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3 years ago

What season is it when the earth axis is tilted so that it is facing toward the sun?

Physics

2 answers:

iVinArrow [24]3 years ago

5 0

Summer (but only in the northern hemisphere)

Tpy6a [65]3 years ago

3 0

C summer because of the tilt but it could be spring due to the rotation.

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An electron is released from rest in a weak electric field given by E =-2.30 x 10-10 N/Cj. After the electron has traveled a ver

Goshia [24]

Explanation:

It is given that,

An electron is released from rest in a weak electric field of, $E=2.3\times 10^{-10}\ N/C$

Vertical distance covered, $s=1\ \mu m=10^{-6}\ m$

We need to find the speed of the electron. Let its speed is v. Using third equation of motion as :

$v^2-u^2=2as$

$v^2=2as$ .............(1)

Electric force is $F_e$ and force of gravity is $F_g$ . As both forces are acting in downward direction. So, total force is:

$F=mg+qE$

$F=9.1\times 10^{-31}\times 9.8+1.6\times 10^{-19}\times 2.3\times 10^{-10}$

$F=4.57\times 10^{-29}\ N$

Acceleration of the electron, $a=\dfrac{F}{m}$

$a=\dfrac{4.57\times 10^{-29}\ N}{9.1\times 10^{-31}\ kg}$

$a=50.21\ m/s^2$

Put the value of a in equation (1) as :

$v=\sqrt{2as}$

$v=\sqrt{2\times 50.21\times 10^{-6}}$

v = 0.010 m/s

So, the speed of the electron is 0.010 m/s. Hence, this is the required solution.

6 0

3 years ago

Larger animals use proportionately less energy than smaller animals; that is, it takes less energy per kg to power an elephant t

marin [14]

Answer:

Part a)

$Q = 952 cal/day$

Part b)

$P = 46 Watt$

Part c)

$\Delta P = 54 W$

Explanation:

As we know that 5000 kg African elephant requires 70,000 Cal for basic needs per day

so we will have

$m = 5000 kg$

$Q = 70,000 Cal$

so we have energy required per kg

$E = \frac{70,000}{5000}$

$E = 14 cal/kg$

Part a)

now we know that per kg the energy required will be same

so we have mass of the human is 68 kg

so energy required per day is given as

$Q = 68 \times 14$

$Q = 952 cal/day$

Part b)

Resting power is the rate of energy in Joule required per sec

so it is given as

$P = \frac{952 \times 4186}{24\times 3600}$

$P = 46 Watt$

Part c)

resting power given in the book is

$P' = 100 W$

so this is less than the power given

$\Delta P = 100 - 46$

$\Delta P = 54 W$

6 0

3 years ago

A campground official wants to measure the distance across an irregularly-shaped lake, but can't do so directly. He picks a poin

sleet_krkn [62]

Answer:

149 m

Explanation:

The distances across the lake is forming a triangle.

let the distance between the point and the left side be 'x'

and the distance between the point and the right be 'y'

and the distance across the lake be 'z' and the angle opposite to 'z' be 'Z' given:

∠Z = 83°

x = 105 m

y = 119 m

Now, applying the Law of Cosines, we get

z² = x² + y² - 2xycos(Z)

Substituting the values in the above equation, we get

z² = 105² + 119² - 2×105×119×cos(83°)

z = √22140.48

z = 148.796 m ≈ 149 m

The point is 149 m across the lake

8 0

3 years ago

Find the frequency of a wave with a period of 0.5 seconds

strojnjashka [21]

Frequency of the wave is 2 per second

Explanation:

Frequency is the number of times waves pass at a particular point of time. Here, time period = 0.5 s

Frequency is given by the formula

f = 1/T, where f is the frequency and T is the time period

⇒ f = 1/0.5 = 2 per second

8 0

3 years ago

A pipe originally has a radius of 1.25m. It narrows down to a radius of 0.55m. If the original force in the big pipe is 72N, wha

Gemiola [76]

Use direct proportionality: If 1.25 m = 72 N, then 0.55 m = y

0.55 m × 72 = 39.6.

39.6÷1,25 gives you your answer which is 31.68 N.

5 0

3 years ago