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Elena-2011 [213]
2 years ago
5

A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for

7.9 seconds. How far did the truck travel during that time interval?
Physics
1 answer:
Sonja [21]2 years ago
8 0

Answer:

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

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Answer:

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Explanation:

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The horizontal velocity of a body can be calculated as shown below.\

Vh = Vcos∅.......................... Equation 1

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Substitute into equation 1

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2 years ago
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Here, R=109677 cm^{-1}.

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Now,

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