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Elena-2011 [213]
3 years ago
5

A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for

7.9 seconds. How far did the truck travel during that time interval?
Physics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

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What is the distance to a star whose parallex is 0.1 sec?
Arte-miy333 [17]

Answer:

30.86\times 10^{13} km

Explanation:

Given the parallex of the star is 0.1 sec.

The distance is inversely related with the parallex of the star. Mathematically,

d=\frac{1}{P}

Here, d is the distance to a star which is measured in parsecs, and P is the parallex which is measured in arc seconds.

Now,

d=\frac{1}{0.1}\\d=10 parsec

And also know that,

1 parsec=3.086\times 10^{13} km

Therefore the distance of the star  is 30.86\times 10^{13} km away.

6 0
3 years ago
Determine the velocity (in m/s) of the object at 10seconds. Include a numerical answer accurate to the first decimal place. If n
tatuchka [14]

Answer:

v = 0.5 [m/s]

Explanation:

In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.

The slope of a line is determined by the following mathematical expression.

P₂ = point 2 = (12,12) = (x₂,y₂)

P₁ = Point 1 = (6,9) = (x₁,y₁)

In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.

Now using the slope:

m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5

This slope is equal to the speed (velocity)

v = 0.5 [m/s]

8 0
3 years ago
Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c
11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}

And plug in the numbers we are given:

\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}

Learn more about ideal gases: brainly.com/question/26450101

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3 years ago
Density of salty water as compared to the density of pure water is
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The answer of this question is (c) is always more
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Describe in short the working system of a water pump ​
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