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Elena-2011 [213]
3 years ago
5

A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for

7.9 seconds. How far did the truck travel during that time interval?
Physics
1 answer:
Sonja [21]3 years ago
8 0

Answer:

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s(the distance travelled)...u(the initial velocity)...t(the time period)

; s = 6.6(7.9) + 1/2 (2.8)(7.9)^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m

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The minimum thickness of the soap bubble for destructive interference to occur is 225.56 nm.

Explanation:

Given;

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t = \frac{\lambda}{2n} \\\\t = \frac{600*10^{-9}}{2(1.33)}\\\\t = 2.2556 *10^{-7} \ m\\\\t =  225.56 *10^{-9} \ m\\\\t = 225.56 \ nm

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r = radius of the orbit of moon around the earth = 3.85\times10^{8} m

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According to Kepler's third law, Time period is related to radius of orbit as

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inserting the values, we get

T^{2} = \frac{4(3.14)^{2} (3.85\times10^{8})^{3}  }{(6.67\times10^{-11})(5.98\times10^{24})}\\T = 2.3754\times10^{6} sec

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