Answer:
6.68 X 10^-11
Explanation:
From the second Ka, you can calculate pKa = -log (Ka2) = 6.187
The pH at the second equivalence point (8.181) will be the average of pKa2 and pKa3. So,
8.181 = (6.187 + pKa3) / 2
Solving gives pKa3 = 10.175, and Ka3 = 10^-pKa3 = 6.68 X 10^-11
<span>The Law of Conservation of Mass simply states
that the total amount of mass should not change in a chemical reaction that is
isolated (no other objects can enter the reaction). The total mass of the
reactants must be equal to the total mass of the products. Thus, t</span>he correct estimate of
the amount of oxygen used in the interaction is the difference between 133
g and 29 g.
ANSWER

EXPLANATION
Given that;
The two reactants are KBr and CaO
Double replacement reaction is a type of chemical reaction that occur when two reactants exchange cations and anions to yield new products.

Therefore, the resulting products of the given data are K2O + CaBr2
The correct answer is option B
Answer:
Ag is the oxidizing agent
Explanation:
oxidizing agent in the following equation?
Al (s) + 3 Ag+ (aq) = Al+3 (aq) + 3 Ag (s)
Left side
Al = 1
Ag = 3
Right Side
Al = 1
Ag = 3
So it's balanced already good.
Define
oxidizing agent = An oxidizing agent is the substance that gains electrons and is reduced in a chemical reaction.
Al is the reducing agent.
Ag is the oxidizing agent
Answer:

Explanation:
Hello there!
Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:
![K=\frac{[NO_2]^2}{[NO]^2[O_2]}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BNO%5D%5E2%5BO_2%5D%7D)
Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.
Best regards!