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3 years ago

In which of the following reactions does a decrease in the volume of the reaction vessel at constant

Chemistry

1 answer:

Black_prince [1.1K]3 years ago

6 0

Answer:

The correct option is: A) 2H₂(g) + O₂(g) → 2H₂O(g)

Explanation:

According to the Le Chatelier's principle, change in the volume of the reaction system causes equilibrium to shift in the direction that reduces the effect of the volume change.

When the volume decreases then the pressure of the reaction vessel increases, then the equilibrium shifts towards the reaction side that produces less number of moles of gas.

A) 2H₂(g) + O₂(g) → 2H₂O(g)

The number of moles of reactant is 3 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the product side, thereby favoring the formation of products.

B) NO₂(g) + CO(g) → NO(g) + CO₂(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

C) H₂(g) + I₂(g) → 2HI(g)

The number of moles of reactant and product both is 2.

Therefore, when the volume decreases, the equilibrium does not shift in any direction.

D) 2O₃(g) → 3O₂(g)

The number of moles of reactant is 2 and number of moles of product is 3.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

E) MgCO₃(s) → MgO(s) + CO₂(g)

The number of moles of reactant is 1 and number of moles of product is 2.

Therefore, when volume decreases, the equilibrium shifts towards the reactant side, thereby favoring the formation of reactants.

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In an experiment, 4.14 g of phosphorus combined with chlorine to produce 27.8 g of a white solid compound. what is the empirical

Umnica [9.8K]

Grams of Phosphorus = 4.14 grams
Grams of white compound = 27.8 grams
Grams of Chlorine would be = 27.8 - 4.14 = 23.66 grams
Calculating moles which would be grams / molar mass
Molar mass of P = 30.97 grams / moles; Molar mass of Cl = 35.45 grams / moles
Moles of Phosphorus = 4.14 grams / 30.97 grams / moles = 0.1337 moles
Moles of Chlorine = 23.66 grams / 35.45 grams / moles = 0.6674 moles
Calculating the ratios by dividing with the small entity
P = 0.1337 moles / 0.1337 moles = 1
Cl = 0.6674 moles / 0.1337 moles = 5
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How many photons are produced in a laser pulse of 0.497 J at 469 nm?

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E=hν where E is the energy of a single photon, and ν is the frequency of a single photon. We recall that a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by λ=cνλ will have an energy given by E=hcλλ=657 nm. This will be E=(6.626×10−34)(2.998×108)(657×10−9)=3.0235×10−19J So we now know the energy of one photon of wavelength 657 nm. To find out how many photons are in a laser pulse of 0.363 Joules, we simply divide the pulse energy by the photon energy or N=Epulse Ephoton=0.3633.0235×10−19=1.2×1018So there would be 1.2×1018 photons of wavelength 657 nm in a pulse of laser light of energy 0.363 Joules.

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The student's lab manual says to mix some of his Na2CO3 solution with an aqueous solution of copper(II) sulfate (CuSO4)

lord [1]

Explanation:

When the student mixed the solution sodium carbonate with solution of copper(II) sulfate ; Copper Hydroxocarbonate , sodium sulfate and carbon dioxide gas was obtained as a products.

The balanced chemical reaction

$2Na_2CO_3+2CuSO_4\rightarrow Cu_2(OH)_2CO_3+2Na_2SO_4+CO_2$

Where:

$Cu_2(OH)_2CO_3$ = Copper(II) Hydroxocarbonate

$Na_2CO_3$ = Sodium carbonate

$CuSO_4$ = Copper(II) sulfate

$Na_2SO_4$ = Sodium sulfate

$CO_2$ = Carbon-dioxide

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3 years ago

How many sublevels inn the second energy level?

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There are two subshells that are s and p, which are present in the second energy level.

The energy level can be defined as the fixed distances from the nucleus of an atom where electrons may be found. Each energy level is divided into some Subshells. These subshells are known as s-subshell, p-subshell, d-subshell, and f-subshell. This subshell contains some orbitals, these orbitals are the place where there is the maximum probability of getting the electrons. In one orbital, a maximum of two electrons can be present.

Hence, there are two subshells in the second energy level.

Learn more about subshells here:

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