<u>¹⁴₇N</u><u> </u>is the more stable isotope
<h3>
Briefly explained</h3>
We have ¹⁴₇N which has a neutron to proton ratio of one, and we look at ¹⁸₇N which has a neutron to proton ratio of 1.57 Again, you look at table 24 to and you see the atomic number of seven and there is really no stable isotope. It has any more than 10 neutrons.
When we have eight, protons will go down seven protons. There's really nothing stable that has more than maybe eight neutrons. So the fact that we have 11 neutrons with ¹⁸₇N suggests that this is very unstable and
¹⁴₇N is the stable isotope of the pair.
<h3>
Stable and Unstable Nuclei</h3>
An atom is electrically neutral. It contains an equal number of positively charged protons and negatively charged electrons and their charges balance. The nucleus however contains only positively charged protons which are closely packed together in a very small volume (remember neutrons have no charge).
From the laws of physics (Coulomb’s Law) one would expect that the protons being of the same charge and so close together would exert strong repulsive forces on each other. The combined gravitational force from the protons and neutrons in a nucleus is insignificant as an attractive force because their masses are so tiny.
This implies there must be an additional attractive force similar in size to the electrostatic repulsion which holds the nucleus together.
Learn more about stable and unstable nuclei
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Answer:
Look at the periodic table of elements
Explanation:
Group 1 is the most reactive and to the right
Group 18 is least reactive and all the way to the left. The rest are in between. The groups go vertical.
You'd be able to solve with this information youre welcome
Answer : The mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.
Explanation :
Law of multiple proportion : It states that when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.
As we are given that the mass of ratio of carbon and oxygen in CO is 1 gram and 1.33 gram.
Ratio of C and O in CO = 1 : 1
Ratio of C and O in CO₂ = 1 : 2
So, the mass of ratio of carbon and oxygen in CO₂ will be 1 gram and (2×1.33) 2.66 gram.
Thus, the mass of oxygen combined with 1.00 g of carbon in carbon dioxide will be, 2.66 grams.
Answer:
Keq = [CO₂]/[O₂]
Explanation:
Step 1: Write the balanced equation for the reaction at equilibrium
C(s) + O₂(g) ⇄ CO₂(g)
Step 2: Write the expression for the equilibrium constant (Keq)
The equilibrium constant is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species. The equilibrium constant for the given system is:
Keq = [CO₂]/[O₂]
