II. sulfur (S) and carbon (C)
and
III. fluorine (F) and oxygen (O)
will form covalent bonds, so the answer will be:
e. II and III
Explanation:
To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.
If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.
If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)
If the electronegativity difference is greater then 1.8 there is an ionic bond.
We have the following cases:
I. lithium (Li) and sulfur (S)
electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic
II. sulfur (S) and carbon (C)
electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent
III. fluorine (F) and oxygen (O)
electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.
Learn more about:
covalent and ionic bonds
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The hybrid orbital of this molecule is 
. Hence, option C is correct.
<h3>What is hybridisation?</h3>
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound, a hybrid orbital makes I-O bonds. Due to hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of 
the ion is pyramidal.
The hybrid orbital of this molecule is . Hence, option C is correct.
Learn more about hybridisation here:
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Answer:
Explanation:
6CO₂ + 6 H₂O ⇄ C₆H₁₂0₆ + 6O₂
This is the chemical equation given .
1. The equation shows a __Chemical equation_______the breaking and forming of chemical bonds that leads to a change in the composition of matter.
2. In the equation, CO₂ is a___reactant_____.
3. In the equation, C₆H₁₂0₆ is a ___product________.
4. In O₂, the type of bond that holds the two oxygen atoms together is a_nonpolar_covalent bond_________.
5. In H₂O, the type of bond that holds one of the hydrogen atoms to the oxygen atom is a__polar_hydrogen bond____.
6. The number of oxygen atoms on the left side of the equation is__equal to_________ the number of oxygen atoms on the right side.
Answer :
AgBr should precipitate first.
The concentration of 
when CuBr just begins to precipitate is, 
Percent of remains is, 0.0018 %
Explanation :
for CuBr is 
for AgBr is 
As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgBr has a smaller than CuBr then AgBr should precipitate first.
Now we have to calculate the concentration of bromide ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
![K_{sp}=[Cu^+][Br^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BCu%5E%2B%5D%5BBr%5E-%5D)
![4.2\times 10^{-8}=0.073\times [Br^-]](https://tex.z-dn.net/?f=4.2%5Ctimes%2010%5E%7B-8%7D%3D0.073%5Ctimes%20%5BBr%5E-%5D)
![[Br^-]=5.75\times 10^{-7}M](https://tex.z-dn.net/?f=%5BBr%5E-%5D%3D5.75%5Ctimes%2010%5E%7B-7%7DM)
Now we have to calculate the concentration of silver ion.
The solubility equilibrium reaction will be:
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ag^+][Br^-]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BAg%5E%2B%5D%5BBr%5E-%5D)
![7.7\times 10^{-13}=[Ag^+]\times 5.75\times 10^{-7}M](https://tex.z-dn.net/?f=7.7%5Ctimes%2010%5E%7B-13%7D%3D%5BAg%5E%2B%5D%5Ctimes%205.75%5Ctimes%2010%5E%7B-7%7DM)
![[Ag^+]=1.34\times 10^{-6}M](https://tex.z-dn.net/?f=%5BAg%5E%2B%5D%3D1.34%5Ctimes%2010%5E%7B-6%7DM)
Now we have to calculate the percent of remains in solution at this point.
Percent of remains = 
Percent of remains = 0.0018 %
Answer:
mass number
Explanation:
yeah mass number is the total of protons and neutrons
for example carbon has 12 proton and 12 neutrons therefore it's mass number is 24
i hope this is what you're looking for
