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Free_Kalibri [48]
3 years ago
7

The table shows information about for objects resting at the top of a hill. Which object is on the tallest hill?

Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
6 0
The formula for Potential Energy is as follows:

Potential Energy = mass x gravity x height

Begin by inserting any known values into the equation above:

W: 980 = (50)(9.8)(h)
X: 1029 = (35)(9.8)(h)
Y: 1519 = (62)(9.8)(h)
Z: 1176 = (24)(9.8)(h)

Then simplify the right side of each equation:

W: 980 = 490h
X: 1029 = 343h
Y: 1519 = 607.6h
Z: 1176 = 235.2h

Divide the coefficient of “h” from both sides of each equation:

W: (980/490) = h
X: (1029/343) = h
Y: (1519/607.6) = h
Z: (1176/235.2) = h

Simplify the left side of each equation:

W: 2 = h
X: 3 = h
Y: 2.5 = h
Z: 5 = h

Object Z has a height of 5. Object Z is sitting on the tallest hill.

I hope this helps!
Fudgin [204]3 years ago
5 0

Answer:

the answer is z

Explanation:

just took the test and got 100%

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Samantha is refinishing her rusty wheelbarrow. She moves her sandpaper back and forth 45 times over a rusty area, each time movi
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Answer:

W = 12.96 J

Explanation:

The force acting in the direction of motion of the sand paper is the frictional force. So, we first calculate the frictional force:

F = μR

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F = 2.4 N

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d = 5.4 m

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Three equal point charges, each with charge 1.05 μCμC , are placed at the vertices of an equilateral triangle whose sides are of
kirza4 [7]

Answer:

The value is U  = 0.06 \  J

Explanation:

From the question we are told that

The value of charge on each three point charge is

q_1 = q_2 = q_3 =q=  1.05 \mu C  =  1.05 *10^{-6} \  C

The length of the sides of the equilateral triangle is r  =  0.500 \

Generally the total potential energy is mathematically represented as

U  = k *  [ \frac{q_1 *  q_2}{r}  +  \frac{q_2 *  q_3}{r}   + \frac{q_3 *  q_1}{r} ]

=> U  = k * 3 * \frac{q^2}{r}

Here k is coulomb constant with value k = 9*10^{9}\  kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

=>    U  = 9*10^9 * 3 * \frac{(1.05 *10^{-6})^2}{0.5 }

U  = 0.06 \  J

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