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Trava [24]
2 years ago
14

A mixture of reactants and products for the reaction shown below is at

Chemistry
1 answer:
zavuch27 [327]2 years ago
5 0

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

<h3>What is chemical equilibrium? </h3>

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

<h3>Principle of chemical equilibrium </h3>

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

<h3>How to determine what will happen if the volume of the container is increased from 2 L to 4 L</h3>

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

  • Volume of reactants = 1 + 3 = 4 L
  • Volume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

Learn more about chemical equilibrium:

brainly.com/question/4289021

#SPJ1

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A 11.97g sample of NaBr contains 22.34 % Na by mass. Considering the law of constant composition (definite proportions), how man
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<h3>Answer:</h3>

2.125 g

<h3>Explanation:</h3>

We have;

  • Mass of NaBr sample is 11.97 g
  • % composition by mass of Na in the sample is 22.34%

We are required to determine the mass of 9.51 g of a NaBr sample.

  • Based on the law of of constant composition, a given sample of a compound will always contain the sample percentage composition of a given element.

In this case,

  • A sample of 11.97 g of NaBr contains 22.34% of Na by mass
  • Therefore;

A sample of 9.51 g of NaBr will also contain 22.345 of Na by mass

  • But;

% composition of an element by mass = (Mass of element ÷ mass of the compound) × 100

  • Therefore;

Mass of the element = (% composition of an element × mass of the compound) ÷ 100

Therefore;

Mass of sodium = (22.34% × 9.51 g) ÷ 100

                         = 2.125 g

Thus, the mass of sodium in 9.51 g of NaBr is 2.125 g

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How many liters of salt solution will be needed to provide 15 grams of salt if the concentration of the solution is 50 g/l?​
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.30 l

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