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2 years ago

A mixture of reactants and products for the reaction shown below is at

Chemistry

1 answer:

zavuch27 [327]2 years ago

5 0

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

<h3>What is chemical equilibrium? </h3>

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

<h3>Principle of chemical equilibrium </h3>

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

<h3>How to determine what will happen if the volume of the container is increased from 2 L to 4 L</h3>

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

Volume of reactants = 1 + 3 = 4 L
Volume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

Learn more about chemical equilibrium:

brainly.com/question/4289021

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You might be interested in

3 moles of anything is how many particles?

Natali [406]

Answer:

<h2>1.806 × 10²⁴ particles</h2>

Explanation:

The number of particles in a substance can be found by using the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 3 × 6.02 × 10²³

We have the final answer as

<h3>1.806 × 10²⁴ particles</h3>

Hope this helps you

3 0

3 years ago

What is the molar mass of BaBr2? A. 217.2 g/mol B. 297.1 g/mol C. 354.5 g/mol D. 434.4 g/mol

qaws [65]

Answer: Option (B) is the correct answer.

Explanation:

Molar mass is defined as the sum of masses of all the atoms present in a compound.

For example, atomic mass of barium is 137.32 g/mol and atomic mass of bromine is 79.90 g/mol.

Therefore, molar mass of $BaBr_{2}$ will be as follows.

Molar mass = atomic mass of Ba + $2 \times atomic mass of Br$

= 137.32 g/mol + $2 \times 79.90 g/mol$

= 297.12 g/mol

Hence, we can conclude that molar mass of [tex]BaBr_{2}[tex] is 297.12 g/mol.

8 0

3 years ago

Read 2 more answers

A 0.286-g sample of gas occupies 125 ml at 60. cm of hg and 25°

irga5000 [103]

Using the Equation: PV=nRT
Where P is the pressure 60 cmHg or 600 mmHg or 600/760= 0.789 atm
V is the volume 125 ml or 0.125 L, n is the number of moles, R is a constant 0.082057, and T is temperature 25 °C or 298 K;
Therefore:
0.789 × 0.125 = n × 0.082057 × 298
n = 0.0987/24.45
= 0.004036 mol
0.004036 mole has a mass of 0.286 g
Hence; 1 mole has a mass of 0.286/0.004036
= 70.8 g /mol
Therefore the molar mass of the gas is 71 g/mol (2 sfg)

4 0

3 years ago

When the hydrogen atom of one water molecule and the oxygen atom of another molecule come together, an what forms?

VARVARA [1.3K]

H2O I THINK THATS THE ANSWER IT SHOULD FORM WATER IF THATS WHAT YOUR ASKING ? 2 HYDROGENS 1 OXYGEN .

7 0

3 years ago

Blast furnaces extra pure iron from the iron(III) oxide in iron ore in a two step sequence. In the first step, carbon and oxygen

aleksklad [387]

Answer:

The mass of O2 that will produce 10 g of Iron, Fe is 6.0 g

Note: The question is missing some details. The complete question is given below:

Blast furnaces extra pure iron from the iron (III) oxide in iron ore in a two step sequence. In the first step, carbon and oxygen react to form carbon monoxide 2C(s)+O2(e) -2CO(« In the second step, iron(III) oxide and carbon monoxide react to form iron and carbon dioxide Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3CO2(g) Suppose the yield of the first step is 90.% and the yield of the second step is 79.%. Calculate the mass of oxygen required to make 10 g of iron. Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits.

Explanation:

Equation for the two reactions is given below:

Step 1: 2C(s) + O2(g) → 2CO(g)

Step 2: Fe2O3(s) + 3CO(g) → 2Fe(s) + 3CO2(g)

In the second step 3 moles of CO reacts to produce 2 moles of Fe

Molar mass of CO = 28 g/mol, molar mass of Fe = 56 g/mol

Therefore, 84 g (3 × 28) of CO will produce 112 g (2 × 56) of Fe

10 g of Fe will be produced by 84/112 × 10 g of CO = 7.5 g of CO

However, the actual yield is 79%, therefore, 7.5 g of CO will produce 0.79 × 10 g of Fe = 7.9 g of Fe

Mass of CO that will produce an actual yield of 10 g of Fe = 7.5/7.9 × 10 = 9.50 g of CO

From the first step:

1 mole of O2 reacts to produce 2 moles of CO (molar mass of O2 = 32 g)

32 g of O2 produces 56 g (2 × 28 g) of CO

Mass of O2 that will produce 9.50 g of CO = 32/56 × 9.50 g = 5.43g

However, since the actual yield is 90%, therefore, mass of CO produced = 0.9 × 9.50 = 8.55 g of CO

Mass of O2 that will produce 9.50 g of CO = 5.43/8.55 × 9.50 g = 6.03 g

Therefore, mass of O2 that will produce 10 g of Iron, Fe is 6.0 g

5 0

3 years ago