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Trava [24]
1 year ago
14

A mixture of reactants and products for the reaction shown below is at

Chemistry
1 answer:
zavuch27 [327]1 year ago
5 0

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

<h3>What is chemical equilibrium? </h3>

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

<h3>Principle of chemical equilibrium </h3>

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

<h3>How to determine what will happen if the volume of the container is increased from 2 L to 4 L</h3>

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

  • Volume of reactants = 1 + 3 = 4 L
  • Volume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

Learn more about chemical equilibrium:

brainly.com/question/4289021

#SPJ1

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I'm not 100% sure of the answer. Explanations are highly appreciated.
PolarNik [594]

Answer:

The correct answer is

B.

\Delta H=2(1072)+498 -4(799)

Explanation:

Enthalpy of reaction :

It is the amount of energy released/absorbed when one mole of the substance is formed from the reactant at a constant pressure.

The enthalpy of a reaction can be calculated using :

\Delta H=\Delta H_{reactants}-\Delta H_{products}

2CO+O_{2}\rightarrow 2CO_{2}

\Delta H_{reactants}=2(C\equiv O)+O=O

\Delta H_{reactants}=2(1072)+498

H_{products}=2(2\times C=O)

H_{products}=4\times 799

\Delta H=\Delta H_{reactants}-\Delta H_{products}

\Delta H=2(1072)+498 -4(799)

units = \frac{kJ}{mole}

Please note that :

The carbon monoxide , CO should be taken as C triple bond O. Not C=O .

So , the bond energy =1072 is used

\Delta H=2(1072)+498 -4(799)

8 0
3 years ago
N2(g) + 3H2(g) → 2NH3(g) How many grams of N2 are required to produce 240.0g NH3?
just olya [345]

Answer:

\large \boxed{\text{197.4 g}}

Explanation:

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:     28.01               17.03

            N₂ + 3H₂ ⟶ 2NH₃

m/g:                          240.0

(a) Moles of NH₃

\text{Moles of NH}_{3} = \text{240.0 g NH}_{3}\times \dfrac{\text{1 mol NH}_{3}}{\text{17.03 g NH}_{3}}= \text{14.09 mol NH}_{3}

(b) Moles of N₂

\text{Moles of N$_{2}$} = \text{14.09 mol NH}_{3} \times \dfrac{\text{1 mol N$_{2}$}}{\text{2 mol NH}_{3}} = \text{7.046 mol N$_{2}$}

(c) Mass of N₂

\text{Mass of N$_{2}$} =\text{7.046 mol N$_{2}$} \times \dfrac{\text{28.01 g N$_{2}$}}{\text{1 mol N$_{2}$}} = \textbf{197.4 g N$_{2}$}\\\\\text{The reaction requires $\large \boxed{\textbf{197.4 g}}$ of N$_{2}$}

7 0
2 years ago
Read 2 more answers
What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of 0.35 atm and water vapor at a par
Fofino [41]
According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure<span> exerted is the sum of the </span>partial pressures<span> of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, </span>oxygen<span> is non-reactive with </span>water vapor<span>.</span>
5 0
3 years ago
The temperature of a gas is 30 degrees Celsius and its pressure is 760 torr. If the temperature originally
erastova [34]
T₁ = 40°C + 273.15 = 313.15 Kelvin T₂ = 30°C + 273.15 = 303.15 Kelvin

Solving Gay-Lussac's Law for P₁ we get:
P₁ = P₂ • T₁ ÷ T₂ P₁ = 760 torr • 313.15 K ÷ 303.15 K P₁ = 785.07 torr

Using the calculator, we click on the P1 button.
We then enter the 3 numbers 760 313.15 and 303.15 into the correct boxes then click "CALCULATE" and get our answer of 785.07 torr.
6 0
3 years ago
Which salt is formed whenHCI is mixed with the sodium hydroxide write formula equation?​
IRISSAK [1]
NaOH + HCl → H2O and NaCl.
8 0
2 years ago
Read 2 more answers
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