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Jobisdone [24]
3 years ago
11

Technetium has a half-life of six hours. If you obtain 100g of a pure technetium sample, after 18 hours how much of the pure sub

stance will be remaining?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer: 12.5 grams.

Explanation:

You can find the amount of pure substance remaining by using the half-life formula:

Q_{1}=Q(\frac{1}{2})^{\frac{t}{t2} }

Where t is the amount of time, and t2 is the half life of the substance.

Substituting our values for the variables, we get this equation:

Q_{1} = 100(\frac{1}{2})^3\\\\Q_{1} = 100(\frac{1}{8})\\\\Q_{1} = 12.5

After 18 hours, there will be 12.5 grams of the substance remaining.

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Explanation:

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149.3 g of H2O at 95 ◦C is poured over 412 g Fe at 5 ◦C in an insulated vessel. What is the final temperature? The specific heat
abruzzese [7]
You are correct, but you needn't worry about the signs so much. Just remember that the negative sign is used to denote a loss of energy; since the water is hotter, it will be losing energy (-Q) and the iron will gain energy (Q). Now, we substitute the values:
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6 0
2 years ago
HELP ME PLEASE (brainliest)
Aloiza [94]

Answer: i would say D or the last one.

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Hope this helps :) Can u plz mark me branliest

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