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Jobisdone [24]
3 years ago
11

Technetium has a half-life of six hours. If you obtain 100g of a pure technetium sample, after 18 hours how much of the pure sub

stance will be remaining?
Chemistry
1 answer:
Butoxors [25]3 years ago
5 0

Answer: 12.5 grams.

Explanation:

You can find the amount of pure substance remaining by using the half-life formula:

Q_{1}=Q(\frac{1}{2})^{\frac{t}{t2} }

Where t is the amount of time, and t2 is the half life of the substance.

Substituting our values for the variables, we get this equation:

Q_{1} = 100(\frac{1}{2})^3\\\\Q_{1} = 100(\frac{1}{8})\\\\Q_{1} = 12.5

After 18 hours, there will be 12.5 grams of the substance remaining.

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Answer:

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Explanation:

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8 0
3 years ago
when copper sulfide is partially roasted in air (reaction with o2), copper sulfite is formed first. subsequently, upon heating,
Lyrx [107]

The question is incomplete, complete question is:

When copper(I) sulfide is partially roasted in air (reaction with oxygen), copper(I) sulfite is formed first. subsequently, upon heating, the copper sulfite thermally decomposes to copper(I) oxide and sulfur dioxide. Write balanced chemical equations for these two reactions.

Answer:

The balanced chemical equations for these two reactions:

2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)

Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)

Explanation:

On  partial roasting of copper sulfide in an air. The balanced chemical reaction is given as:

2Cu_2S(s)+3O_2(g)\rightarrow 2Cu_2SO_3(s)

On further heating of copper(I) sulfite it get decomposes into copper oxide and sulfur dioxide. The balanced chemical reaction is given as:

Cu_2SO_3(s)\overset{heat}\rightarrow Cu_2O(s)+SO_2(g)

5 0
3 years ago
What molality of a nonvolatile, nonelectrolyte solute is needed to raise the boiling point of water by 7.10°c (kb = 0.520°c/m)?
faltersainse [42]
According to boiling point elevation equation:
Δ T = i Kb m
when ΔT (change in boiling point) = 7.10 C° 
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m = 7.1 / 0.52 = 13.65 m
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4 years ago
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