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Neporo4naja [7]
2 years ago
13

NH3 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs

on the central atom 5. Electronic geometry: 6. Molecular geometry with ideal bond angles 7. Hybridization of central atom 8. Polarity:
Chemistry
1 answer:
Stels [109]2 years ago
3 0

This question will be answered in parts:

<h3><u>1. Lewis Structure</u></h3>

There are three N-H bonds and one lone pair on the nitrogen atom in the Lewis structure of NH3. On hydrogen atoms, there are no lone pairs that can only hold two electrons.

The lewis structure is as shown in the diagram.

<h3><u>2. Perspective Drawing</u></h3>

A molecule is shown from a viewpoint with its atoms' bonds pointing either in your direction (bolded wedge) or away from you (hash wedge).

The perspective drawing of NH3 is given here

<h3><u>3.Number of atoms bonded to central atom </u></h3>

Nitrogen is the central atom in the Lewis structure of NH3, which also contains one lone pair and is bound to the three hydrogen atoms.

<h3><u>4.Number of non-bonding electron pairs on the central atom</u></h3>

Three bond pairs and two lone pairings exist. This is due to the fact that nitrogen contains five electrons in its outer shell, three of which are bound to hydrogen atoms and two of which are free.

<h3><u>5. Electronic geometry:</u></h3>

The electronic geometry of nitrogen is based on a tetrahedral arrangement of electron pairs, and ammonia likewise possesses four electron pairs. There is only one lone pair because there are only three connected groupings. But since the lone pairs are "invisible," the ammonia has a pyramidal form.

<h3><u>6. Molecular geometry with ideal bond angles</u></h3>

The molecular geometry of ammonia it has a trigonal pyramidal or distorted tetrahedral structure.

The bond angle in ammonia is less than the standard 109.5⁰. The bond angle is 107⁰

<h3><u>7.Hybridization of central atom</u></h3>

The core nitrogen (N) atom in the NH3 molecule has a steric number of (3 + 1) = 4, which causes Sp3 hybridization.

<h3><u>8. Polarity:</u></h3>

Because of its asymmetrical form, a trigonal pyramidal structure, and the different electronegativities of N(3.04) and H(2.2), the NH3 (ammonia) molecule is polar in nature .

To know more about ammonia, you can refer to:

brainly.com/question/13960908

#SPJ4

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A rigid tank is divided into two equal volumes. One side contains 2 kmol of nitrogen N2 at 500 kPa while the other side contains
k0ka [10]

Answer:

The partial pressure of the CO_2 in the final mixture is 200 kPa.

Explanation:

Pressure of nitrogen gas when the two tanks are disconnected = 500 kPa

Pressure of the carbon-dioxide gas when the two tanks are disconnected = 200 kPa

Moles of nitrogen gas =n_1= 2 kmol

Moles of carbon dioxide gas =n_2=8 kmol

After connecting both the tanks:

The total pressure of the both gasses in the tank = p = 250 kPa

According to Dalton' law of partial pressure:

Total pressure is equal to sum of partial pressures of all the gases

Partial pressure of nitrogen =p_{N_2}^o

Partial pressure of carbon dioxide=p_{CO_2}^o

p_{N_2}^o=p\times \frac{n_1}{n_1+n_2}

p_{N_2}^o=250 kPa\times \frac{0.2}{0.2+0.8}=50 kPa

p_{CO_2}^o=p\times \frac{n_2}{n_1+n_2}

p_{CO_2}^o=250 kPa\times \frac{0.8}{0.2+0.8}=200 kPa

The partial pressure of the CO_2 in the final mixture is 200 kPa.

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when obtaining energy, why mushrooms are more like elephants eating and not like dandelions absorbing sunlight.
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Because they lack chlorophyll (a green pigment in plants that helps them trap sunlight, used to manufacture their food through photosynthesis)

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When iron nail is ground into powder, it’s mass
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(a) The mass of an object remains the same always. It is independent of its location. In this case, an iron nail is ground into powder.

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4 years ago
What is the overall (X-fold) dilution of 4 serial 2-fold dilutions?
svet-max [94.6K]

Answer:

16-fold dilution.

Explanation:

A serial dilution is any dilution where the concentration decrease by the same quantity in each successive step. So, for a 2-fold dilution, the concentration decrease 1/2, it means that if we have a sample with 10 M of concentration, after a 2-fold dilution it will be 5 M. For the next step it will be 1/2 of 5= 2.5 M, and successively.

Then, we just multiply the factor for each dilution. After 4 serial dilutions:

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