Answer:
<u>Hey</u><u> </u><u>buddy</u><u>,</u>
Partial pressure of a gas is calculated by <u>Multiplying</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>pressure</u><u> </u><u>by</u><u> </u><u>mole</u><u> </u><u>fraction</u><u> </u><u>of</u><u> </u><u>that</u><u> </u><u>gas</u><u>.</u>
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Answer:
There are many ways to figuring this out: you could use a ruler, a calculator or scrap paper.
Explanation:
This is not an actual flat out answer, but it’s helpful methods to getting the answer the next time you are stuck. Hope you are having a nice day. Bless your heart and soul.
Answer:
Cap rocks form the top of reservoirs and create a layer that is impervious to fluid flow By preventing fluids from flowing through it, the fluids are prevented from escaping the reservoir. This applies to oil and gas reservoirs. Oil and gas reservoirs often form in "traps"
Answer:
V₁ = 0.585 L
Explanation:
Given data:
Initial pressure = 151 mmHg
Initial volume = ?
Final pressure = 166 mmHg
Final volume = 0.532 L
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
151 mmHg × V₁ = 166 mmHg × 0.532 L
V₁ = 166 mmHg × 0.532 L / 151 mmHg
V₁ = 88.312mmHg .L /151 mmHg
V₁ = 0.585 L
