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natali 33 [55]
3 years ago
15

____________ properties include melting point, boiling point, strength, and malleability.a.physicalc.chemicalb.reactived.none of

the above
Chemistry
1 answer:
lina2011 [118]3 years ago
8 0
Physical properties are those which can be observed without any change in composition of the substance. Hence, a is the answer.
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18. What is the percent by mass sugar of a solution made by dissolving 12.45 grams of sugar in 100 grams of water?
Fantom [35]

The percent by mass sugar of a solution : 11.07%

<h3>Further explanation</h3>

Given

mass of sugar = 12.45 g

mass of water = 100 g

Required

The percent by mass

Solution

Mass of solution :

\tt mass~sugar+mass~water=12.45+100=112.45~g

Percent mass of sugar :

\tt \%mass=\dfrac{mass~sugar}{mass~solution}\times 100\%\\\\\%mass=\dfrac{12.45}{112.45}\times 100\%=11.07\%

6 0
2 years ago
Canadian fans of Justin bieber and Drake . ​
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Answer:

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Explanation:

6 0
3 years ago
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Given the following values for the heats of formation, what is the number of moles of ethane (C2H6, MW 30.0) required to produce
baherus [9]

Answer:

0.641 moles of ethane

Explanation:

Based on the equation:

C2H6(g) + 7/2O2(g) → 2CO2(g) + 3H2O(l)

We can determine ΔH of reaction using Hess's law. For this equation:

<em>Hess's law: ΔH products - ΔH reactants</em>

ΔH = {2ΔHCO2 + 3ΔHH2O} - {ΔHC2H6}

<em>Pure monoatomic substances have a ΔH = 0kJ/mol; ΔHO2 = 0kJ/mol</em>

<em />

ΔH = {2*-393.5kJ/mol + 3*-285.8kJ/mol} - {-84.7kJ/mol}

ΔH = -1559.7kJ/mol

That means when 1 mole of ethane is in combustion there are released 1559.7kJ of heat. To produce 1.00x10³kJ there are needed:

1.00x10³kJ * (1mole ethane / 1559.7kJ) =

<h3>0.641 moles of ethane</h3>
7 0
2 years ago
12. Complete each of the following word equations for synthesis reactions.
Vlada [557]

Explanation:

12)

a) Sodium + oxygen = ?

When sodium reacts oxygen its forms sodium oxide as a product.

4Na(s)+O_2(g)\rightarrow 2Na_2O(s)

b) magnesium + fluorine = ?

When magnesium reacts with fluorine its forms magnesium fluoride as a product.

Mg(s)+F_2(g)\rightarrow MgF_2(s)

13)

a) 2HgO(s)\overset{\Delta }\rightarrow 2Hg(l)+O_2(g)

Decomposition of mercury(II) oxide on heating gives out mercury and oxygen gas.

b)2H_2O(l)\overset{Electricity}\rightarrow 2H_2(g)+O_2(g)

The electrolytic decomposition of water gives out hydrogen gas amd oxygen gas.

5 0
3 years ago
If a gas sample has a pressure of 30.7 kpa at 0.00, by how many degrees celsius does the temperature have to increase to cause t
Otrada [13]
Pressure of the gas P1 = 30.7 kpa  
When it doubled P2 = 61.4 kpa  
Temperature T1 = 0 => T1 =. 0 + 273 =273 
Temperature T2 =? 
We have pressure temperature equation P1T1 = P2T2
 => T2 = P1T1 / P2 = (30.7 x 273) / 61.4 = 136.5 
 So the temperature for doubling the pressure is 136.5.
8 0
3 years ago
Read 2 more answers
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