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aalyn [17]
1 year ago
10

The cricket ball has a mass of 0.16kg and it hits the bat with a speed of 25 m/s. After being in contact with the bat for 0.0013

s, the ball rebounds with a speed of 22 m/s in the direction exactly opposite to its original direction.
A) state the difference between speed and velocity
B) calculate.
I) the change in velocity of the cricket ball
Ii) the average acceleration of the ball whilst it is in contact with tge bat
Iii) the average force exerted on the ball by the bat​
Physics
1 answer:
zavuch27 [327]1 year ago
7 0

change in velocity is 3m/s,the force exterted by bat on ball is 4.8N and the acceleration is 30m/s².

<h3>Give  some difference between velocity and speed.</h3>

1) Speed is scalar quantity but velocity is vector quantity.

2) Speed is distance followed by an individual with respect to  time and velocity is displacement with respect to time .

1) final velocity- intial velocity

 25-22= 3m/s

2) The force is

F= ma

 . 0.16×30= 4.8N

to learn more about speed and velocity click brainly.com/question/19425181

#SPJ9

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A ball is dropped from the top of a building.After 2 seconds, it’s velocity is measured to be 19.6 m/s. Calculate the accelerati
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acceleration, a = 9.8 m/s²

Explanation:

'A ball is dropped from the top of a building' indicates that the initial velocity of the ball is zero.

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t = 2s, v = 19.6 m/s

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Determine the change in electric potential energy of a system of two charged objects when a -2.1-C charged object and a -5.0-C c
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Answer:

Change in electric potential energy ∆E = 365.72 kJ

Explanation:

Electric potential energy can be defined mathematically as:

E = kq1q2/r ....1

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q1 = charge 1 = -2.1C

q2 = charge 2 = -5.0C

∆r = change in distance between the charges

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r2 = 160km = 160000m

From equation 1

∆E = kq1q2 (1/r2 -1/r1) ......2

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∆E = 94.5 × 10^9 (3.87 × 10^-6) J

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