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Sonbull [250]
3 years ago
15

When the bells are charged up, the left bell acquires a positive charge, the right bell a negative charge. When this occurs, the

nut that is suspended between the two bells experiences a torque (it lines itself up with a line between the two bells) but it doesn't experience a net force. What does this tell us about the charge on the nut
Physics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

Thus simply tells us that The nut has no net charge and so therefore, There will be a negative charge on the left side, and an equal positive charge on the right side

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3 0
3 years ago
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Nataliya [291]

Answer:

A, the amount of charge stored per volt

Explanation:

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2 years ago
A system had 150 kj of work done on it and its internal energy increased by 60 kj. How much energy did the system gain or lose a
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Answer:

The system loses 90 kJ of heat

Explanation:

We can answer the question by using the 1st law of thermodynamics, which states that:

\Delta U=Q-W

where

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W is the work done by the system (positive if done by the system, negative if done by the surrounding on the system)

In this problem, we have:

W=-150 kJ is the work done (negative, because it is done by the surrounding on the system)

\Delta U=+60 kJ is the increase in internal energy

Using the equation above, we can find Q, the heat absorbed/released by the system:

Q=\Delta U+W=+60 kJ+(-150 kJ)=-90 kJ

And the negative sign means that the system has lost this heat.

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