The force exerted by a magnetic field on a wire carrying current is:

where I is the current, L the length of the wire, B the magnetic field intensity, and

the angle between the wire and the direction of B.
In our problem, the force is F=0.20 N. The current is I=1.40 A, while the length of the wire is L=35.0 cm=0.35 m. The angle between the wire and the magnetic field is

, so we can re-arrange the formula and substitute the numbers to find B:
Answer:
1 micron = 1.00E-6 m is one way
1.00^-6 m is another but is not usually considered scientific notation, but
often convenient to use.
Answer: 29.17m/s^2
Explanation:
Given the following :
Velocity = 525 m/s
Time = 18 seconds
Acceleration = change in Velocity with time
Using the motion equation:
v = u + at
Where v = final Velocity
u = Initial Velocity and t = time
Plugging our values
525 = 0 + a × 18
525 = 18(a)
a = 525 / 18
a = 29.166666
a = 29.17 m/s^2
Answer:
'A' is the the point on the graph that shows a temperature of 40°C and the time of 25 minutes
Answer:
D. −F
Explanation:
the rest of the answers are
2/3F
The force is represented as a positive quantity and is repulsive.
Electrostatic force is inversely proportional to the square of the distance.
The direction of the force changes, and the magnitude of the force quadruples.
hope this helps sorry if i was too late! :)