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1 year ago

Part C

1 answer:

3 0

Answer: The battery in circuit 3 would run out more quickly when the switches are closed because the two bulbs are brighter, which means the battery is providing more energy to that circuit.

Explanation: Answer from plato

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A positively charged particle is in the center of a parallel-plate capacitor that has charge ±Q on its plates. SUppose the dista

slamgirl [31]

Answer:

Stay the same

Explanation:

First of all, let's find how the capacitance of the capacitor changes.

Initially, it is given by

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

From the formula, we see that the capacitance is inversely proportional to the separation between the plates. In this problem, the distance between the plates is doubled, so the capacitance will be halved:

$C' = \frac{1}{2}C$

The potential difference across the capacitor is given by

$V= \frac{Q}{C}$

where

Q is the charge on the plates

C is the capacitance

We see that the voltage is inversely proportional to the capacitance. We said that the capacitance has halved: therefore, the potential difference across the two plates will double:

$V' = 2 V$

Now we can analyze the electric field between the plates of the capacitor, which is given by

$E=\frac{V}{d}$

we said that:

- The voltage has doubled: V' = 2 V

- The distance between the plates has doubled: d' = 2 d

therefore, the new electric field will be

$E'=\frac{2V}{2d}=\frac{V}{d}=E$

So, the electric field is unchanged. And since the force on the particle at the center is directly proportional to the electric field:

F = qE

Then the force on the particle will stay the same.

4 0

2 years ago

A glass flask whose volume is 1000 cm^3 at a temperature of 1.00Â°C is completely filled with mercury at the same temperature. W

Marat540 [252]

Answer:

the coefficient of volume expansion of the glass is $\mathbf{ ( \beta_{glass} )= 1.333 *10^{-5} / K}$

Explanation:

Given that:

Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³

temperature of the glass flask and mercury= 1.00° C

After heat is applied ; the final temperature = 52.00° C

Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C

Volume of the mercury overflow = 8.50 cm^3 = 8.50 × 10⁻⁶ m³

the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K

The increase in the volume of the mercury = 10⁻³ m³ × 51.00 × 1.80 × 10⁻⁴

The increase in the volume of the mercury = $9.18*10^{-6} \ m^3$

Increase in volume of the glass = 10⁻³ × 51.00 × $\beta _{glass}$

Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask

the mercury overflow = $(9.18*10^{-6} - 51.00* \beta_{glass}*10^{-3})\ m^3$

$8.50*10^{-6} = (9.18*10^{-6} -51.00* \beta_{glass}* 10^{-3} )\ m^3$

$8.50*10^{-6} - 9.18*10^{-6} = ( -51.00* \beta_{glass}* 10^{-3} )\ m^3$

$-6.8*10^{-7} = ( -51.00* \beta_{glass}* 10^{-3} )\ m^3$

$6.8*10^{-7} = ( 51.00* \beta_{glass}* 10^{-3} )\ m^3$

$\dfrac{6.8*10^{-7}}{51.00 * 10^{-3}}= ( \beta_{glass} )$

$\mathbf{ ( \beta_{glass} )= 1.333 *10^{-5} / K}$

Thus; the coefficient of volume expansion of the glass is $\mathbf{ ( \beta_{glass} )= 1.333 *10^{-5} / K}$

5 0

2 years ago

If the mass of a material is 120 grams and the volume of the material is 23 cm3, what would the density of the material be?

oee [108]

The density is 5.22 g/cm³.

Density= $\frac{mass}{volume}$
Density= $\frac{120 g}{23 cm {3} }$
Density= 5.22 g/cm³

4 0

2 years ago

ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give

Alexandra [31]

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: $[tex]velocity=\frac{distance}{time}$ [/tex]

Use the information about the speed of light in vacuum: $300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}$

and the information you are given regarding the distance between Sun and Earth: $1.5 * 10^{11} m$

to solve the first velocity equation for the unknown time "t":

$velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s$

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

5 0

2 years ago

Which properties can be used to determine whether a substance is a liquid or a plasma? Check all that apply.

lapo4ka [179]

Plasma is the state of mater after gases. Its where the gas forms ions. The state is made of charged particles.
So, the best test for plasma is C and D.
The charge of the substance's particles and
The distance between the substance's particles.

6 0

2 years ago

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