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Kruka [31]
3 years ago
11

What is the average acceleration during the time interval 0 seconds to 10 seconds?

Physics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

yea its D  .

Explanation:

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If two wires run parallel and the current passes through both wires in the same direction, which happens to the wires?
pashok25 [27]

If two wires run parallel and the current passes through both wires in the same direction, which happens to the wires?

If two wires run parallel and the current passes through both wires in the same direction, the wires wires move together because the current of one wire pulls the other wire closer. The answer is letter C. 

7 0
3 years ago
The rate at which light energy is radiated from a source is measured in which of the following units?
Tamiku [17]
The correct answer is A. Lumen

This is the so called energy of light measurement. Other mentioned measurements are used for different things such as measuring light over an area of space or similar.
6 0
3 years ago
What will the north poles of two bar magnets do when brought together?
Reika [66]

Answer:

They will repel each other since they have the same charge specifically negative

Explanation:

4 0
3 years ago
Read 2 more answers
What is the Electron Geometry of a AB4 molecule? A. bent B. trigonal planar C. linear D. tetrahedral
34kurt

Answer:

D.Tetrahedral

Explanation:

The central atom has 0 lone pair and 4 bond pairs. Hybridization is sp³. The geometry is tetrahedral which has an angle of 109.5°.

According to VSEPR theory, each molecule arranges itself such that it faces minimum repulsion and the given molecule is of type AB_4.

Therefore the answer will be D.

D.Tetrahedral

4 0
3 years ago
As more and more bulbs are connected in series to a flashlight battery, what happens to the brightness of each bulb? Assuming th
balu736 [363]

Answer:

P_1 = P_2 = \frac{P}{2}

so each bulb brightness becomes half of its given or indicated power

P_1 = P_2 = \frac{V^2}{R}

so both bulb will glow same power as indicated

Explanation:

Let the indicated power on the bulbs is given as P and its rated voltage is V

so here resistance of each bulb is given as

R = \frac{V^2}{P}

now if the two bulbs are connected in series so we will have

R_{eq} = R_1 + R_2

R_{eq} = 2\frac{V^2}{P}

now the current in the circuit is given as

i = \frac{V}{R_{eq}

i = \frac{P}{2V}

now brightness of each bulb is given as

P_1 = P_2 = i^2 R

P_1 = P_2 = \frac{P}{2}

so each bulb brightness becomes half of its given or indicated power

Now if the two bulbs are connected in parallel

then the net voltage across each bulb is "V"

so we will have

P_1 = P_2 = \frac{V^2}{R}

so both bulb will glow same power as indicated

6 0
4 years ago
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