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Kruka [31]
3 years ago
11

What is the average acceleration during the time interval 0 seconds to 10 seconds?

Physics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

yea its D  .

Explanation:

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As altitude increases, what happens to air pressure?
Mashcka [7]

Answer:

It decreases

Explanation:

The air pressure tends to be higher on the places with the lowest altitudes, and lower at the places with higher altitudes. Basically, the air pressure is the wight of the air, and since the air is denser and heavier at the lower altitudes, the air pressure is higher, while on the higher altitudes the air is less dense, thus the air pressure is lower. So in practice we can expect that the air pressure in a low valley will be higher than the air pressure at the top of higher mountain.

3 0
3 years ago
Read 2 more answers
When working with electric charges, what symbol is used in equations to represent the electric field of an object?
Rus_ich [418]

E= electric field

E=F/q= force per unit charge

q= charge

8 0
3 years ago
Read 2 more answers
Find the sum of the following vectors A=3i-12j and B=4i+7j<br><br>​
Lady_Fox [76]

Answer:

(I). The sum of the vectors is (7i-5j).

(II). The sum of the vectors is (8i+7j).

Explanation:

Given that,

(I). Vector A A=3i-12j

Vector B B=4i+7j

Suppose, (II). Vector A A=6i+15j

Vector B B=2i-8j

(I). We need to calculate the sum of the vectors

Using formula of sum

\vec{C}=\vec{A}+\vec{B}

Where,

\vec{A}= vector A

\vec{B}= vector B

\vec{C}= sum of the vector A and bPut the value into the formula[tex]\vec{C}=(3i-12j)+(4i+7j)

\vec{C}=7i-5j

(II). We need to calculate the sum of the vectors

Using formula of sum

\vec{C}=\vec{A}+\vec{B}

Put the value into the formula

\vec{C}=(6i+15j)+(2i-8j)

\vec{C}=8i+7j

Hence, The sum of the vectors is (7i-5j).

The sum of the vectors is (8i+7j).

8 0
3 years ago
In a supermarket, you place a 22.3-N (around 5 lb) bag of oranges on a scale, and the scale starts to oscillate at 2.7 Hz. What
allsm [11]

Answer:

Force constant, k = 653.3 N/m

Explanation:

It is given that,

Weight of the bag of oranges on a scale, W = 22.3 N

Let m is the mass of the bag of oranges,

m=\dfrac{W}{g}

m=\dfrac{22.3}{9.8}

m = 2.27 kg

Frequency of the oscillation of the scale, f = 2.7 Hz

We need to find the force constant (spring constant) of the spring of the scale. We know that the formula of the frequency of oscillation of the spring is given by :

f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

k=4\pi^2 f^2m

k=4\pi^2 \times (2.7)^2\times 2.27

k = 653.3 N/m

So, the force constant of the spring of the scale is 653.3 N/m. Hence, this is the required solution.

7 0
4 years ago
What color is iodine solid and its gas?
elena-14-01-66 [18.8K]
Purple -non black metallic
7 0
3 years ago
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