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2 years ago

Define the upper mantle and the lower mantle as well give both the thickness and temperature

Physics

1 answer:

defon2 years ago

8 0

Answer:

Explanation:

because thats what I put and got it right

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an object of mass 8 kg is whriled round in a vertical circle of radius 2m with a constant speed of 6m/s .Then the maximum and mi

algol13

Answer:

Maximum Tension=224N

Minimum tension= 64N

Explanation:

Given

mass =8 kg

constant speed = 6m/s .

g=10m/s^2

Maximum Tension= [(mv^2/ r) + (mg)]

Minimum tension= [(mv^2/ r) - (mg)]

Then substitute the values,

Maximum Tension= [8 × 6^2)/2 +(8×9.8)] = 224N

Minimum tension= [8 × 6^2)/2 -(8×9.8)]

=64N

Hence, Minimum tension and maximum Tension are =64N and 2224N respectively

5 0

2 years ago

A radar for tracking aircraft broadcasts a 12 GHz microwave beam from a 2.0-m-diameter circular radar antenna. From a wave persp

NISA [10]

A) 750 m

First of all, let's find the wavelength of the microwave. We have

$f=12GHz=12\cdot 10^9 Hz$ is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

So the wavelength of the beam is

$\lambda=\frac{c}{f}=\frac{3\cdot 10^8 m/s}{12\cdot 10^9 Hz}=0.025 m$

Now we can use the formula of the single-slit diffraction to find the radius of aperture of the beam:

$y=\frac{m\lambda D}{a}$

where

m = 1 since we are interested only in the central fringe

D = 30 km = 30,000 m

a = 2.0 m is the aperture of the antenna (which corresponds to the width of the slit)

Substituting, we find

$y=\frac{(1)(0.025 m)(30000 m)}{2.0 m}=375 m$

and so, the diameter is

$d=2y = 750 m$

B) 0.23 W/m^2

First we calculate the area of the surface of the microwave at a distance of 30 km. Since the diameter of the circle is 750 m, the radius is

$r=\frac{750 m}{2}=375 m$

So the area is

$A=\pi r^2 = \pi (375 m)^2=4.42\cdot 10^5 m^2$

And since the power is

$P=100 kW = 1\cdot 10^5 W$

The average intensity is

$I=\frac{P}{A}=\frac{1\cdot 10^5 W}{4.42\cdot 10^5 m^2}=0.23 W/m^2$

4 0

3 years ago

Plzzzzzz help :(((((((((((

OlgaM077 [116]

Answer:

4. a) F

b) E

c) B

d) D

Hope it helps

7 0

2 years ago

Read 2 more answers

How much current is in a circuit that includes a 9.0 volt battery and a bulb woth a resistance of 4.0 ohms

Vitek1552 [10]

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=9/4=2.25 A

7 0

2 years ago

Read 2 more answers

Consider the electric force between a pair of charged particles a certain distance apart. By Coulomb's Law: If instead, the char

Westkost [7]

Answer:

the answer is d

Explanation:

from F=Q1Q2

r².

then wen both charges are doubled

F=2Q1 ×2Q2

r²

F=4Q1Q2

r²

then 4 has to be the factor multiplied by the other part of the equation for it to balance

4F=4Q1Q2

r²

so theoretically the 4 on the LHS can cancel the 4 on the RHS

5 0

2 years ago