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3 years ago

Define the upper mantle and the lower mantle as well give both the thickness and temperature

Physics

1 answer:

defon3 years ago

8 0

Answer:

Explanation:

because thats what I put and got it right

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The focal length of a lens is inversely proportional to the quantity (n-1), where n is the index of refraction of the lens of th

Ainat [17]

Answer:

46.22 cm

Explanation:

The focal refraction, fr is given by

$fr = \frac {c}{(1.572 -1)} = \frac {c}{0 .572}$

The focal red light is given by

$fv = \frac {c}{(1.605 - 1)} = \frac {c}{0.605}$

$\frac {fv}{fr} = \frac {0.572}{0 .605} = 0.945455$

$\frac {1}{fr} = \frac{1}{image} + \frac {1}{object}$ and making fr the subject we obtain

$fr = \frac {image * object}{(image + object)} = \frac {24.00 * 55} {(24.0 + 55)} = 16.70886 cm$

fv = 0.945455* 16.70886 cm = 15.79747 cm

$image = \frac {object * f} {(object - f)} = \frac {15.79747 * 24.0}{(24.0 - 15.79747)} = 46.22222 cm$

Therefore, violet image is approximately 46.22 cm

5 0

3 years ago

What temperature does water freeze at in celsius and fahrenheit?

andre [41]

32 degrees Fahrenheit
And
0 degrees Celsius

4 0

3 years ago

Read 2 more answers

The average distance of the planet mercury from the sun is 0.39 times the average distance of the earth from the sun. How long i

Stels [109]

Answer:

$T_1=0.24y$

Explanation:

Using Kepler's third law, we can relate the orbital periods of the planets and their average distances from the Sun, as follows:

$(\frac{T_1}{T_2})^2=(\frac{D_1}{D_2})^3$

Where $T_1$ and $T_2$ are the orbital periods of Mercury and Earth respectively. We have $D_1=0.39D_2$ and $T_2=1y$ . Replacing this and solving for

$T_1^2=T_2^2(\frac{D_1}{D_2})^3\\T_1^2=(1y)^2(\frac{0.39D_2}{D_2})^3\\T_1^2=1y^2(0.39)^3\\T_1^2=0.059319y^2\\T_1=0.24y$

5 0

3 years ago

Can you help me with this?

Natasha2012 [34]

Answer:

Explanation:

so basically I am domb so I can not help you

4 0

3 years ago

Heather and Matthew take 45 s to walk eastward along a straight road to a store 72 m away. What is their average velocity?

vladimir1956 [14]

Answer:

v = 1.6 m/s

Explanation:

Given that,

Distance, d = 72 m

Time taken, t = 45 s

We need to find their average velocity. Average velocity of an object is given by total distance divided by total time taken.

$v=\dfrac{d}{t}\\\\v=\dfrac{72\ m}{45\ s}\\\\v=1.6\ m/s$

So, their average velocity is 1.6 m/s.

5 0

4 years ago