The distance of separation of the two cars after 12.0 seconds is 102 m
Final velocity, v of A = 12.5 m/s
Final velocity, v of B = 45 m/s
<h3>What are the distance apart of the two car after 12 seconds?</h3>
The distance of separation of the two cars after 12.0 seconds is calculated as follows:
- The distance travelled by A = velocity * time
Distance travelled by A = 12.5 * 12.0
Distance travelled by A = 150 m
Distance travelled by B is calculated as follows:
- Distance, s = ut + 1/2at²
u = 0, t = 12.0, a = 3.5 m/s²
Distance travelled by B = 0 * 12.0 + 1/2 * 3.5 * 12²
Distance travelled by B = 252 m
The distance of separation of the two cars after 12.0 seconds = 252 - 150 The distance of separation of the two cars after 12.0 seconds = 102 m
Final velocity, v of A = 12.5 m/s
Final velocity, v of B is calculated as follow;
v = u + at
v = 0 + 3.5* 12
Final velocity of B, v = 45 m/s
In conclusion, the distance of separation and final velocities are determined from the given values of initial velocity and acceleration.
Learn more about acceleration and velocity at: brainly.com/question/11872016
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