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larisa86 [58]
1 year ago
10

Two cars are traveling from the same point. Car A has a velocity of 12.5 m/s while car B has zero velocity but an acceleration o

f 3.5 m/s 2 . How far apart will the cars be after 12.0 seconds? What are the final velocities for Cars A and B?
Physics
1 answer:
svp [43]1 year ago
7 0

The distance of separation of the two cars after 12.0 seconds is 102 m

Final velocity, v of A = 12.5 m/s

Final velocity, v of B = 45 m/s

<h3>What are the distance apart of the two car after 12 seconds?</h3>

The distance of separation of the two cars after 12.0 seconds is calculated as follows:

  • The distance travelled by A = velocity * time

Distance travelled by A = 12.5 * 12.0

Distance travelled by A = 150 m

Distance travelled by B is calculated as follows:

  • Distance, s = ut + 1/2at²

u = 0, t = 12.0, a = 3.5 m/s²

Distance travelled by B = 0 * 12.0 + 1/2 * 3.5 * 12²

Distance travelled by B = 252 m

The distance of separation of the two cars after 12.0 seconds = 252 - 150 The distance of separation of the two cars after 12.0 seconds = 102 m

Final velocity, v of A = 12.5 m/s

Final velocity, v of B is calculated as follow;

v = u + at

v = 0 + 3.5* 12

Final velocity of B, v = 45 m/s

In conclusion, the distance of separation and final velocities are determined from the given values of initial velocity and acceleration.

Learn more about acceleration and velocity at: brainly.com/question/11872016

#SPJ1

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Consider a transformer. used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 3 turns in i
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Answer:

<em>a) 0.72 V</em>

<em>b) 19.2 mA</em>

<em>c) 2.304 Watts</em>

Explanation:

A transformer is used to step-up or step-down voltage and current. It uses the principle of electromagnetic induction. When the primary coil is greater than the secondary coil, the it is a step-down transformer, and when the primary coil is less than the secondary coil, the it is a step-up transformer.

number of primary turns = N_{p} = 500 turns

input voltage = V_{p} = 120 V

number of secondary turns = N_{s} = 3 turns

output voltage = V_{s} = ?

using the equation for a transformer

\frac{V_{s} }{V_{p} }  = \frac{N_{s} }{N_{p} }

substituting values, we have

\frac{V_{s} }{120 }  = \frac{3 }{500} }

500V_{p}  = 120*3\\500V_{p} = 360

V_{p} = 360/500 =<em> 0.72 V</em>

<em></em>

b) by law of energy conservation,

I_{P}V_{p} = I_{s}V_{s}

where

I_{p} = input current = ?

I_{s} = output voltage = 3.2 A

V_{s} = output voltage = 0.72 V

V_{p} = input voltage = 120 V

substituting values, we have

120I_{p} = 3.2 x 0.72

120I_{p} = 2.304

I_{p}  = 2.304/120 = 0.0192 A

= <em>19.2 mA</em>

<em></em>

c) power input = I_{p} V_{p}

==> 0.0192 x 120 = <em>2.304 Watts</em>

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