A)
1 g/cm³ --------------- 0.001 kg/cm³
5.52 g/cm³------------ ?
5.52 x 0.001 / 1
= 0.00552 kg/cm³
b) 1 g/cm³ ----------- 62.428 lb/ft³
5.52 g/cm³ ------- ?
5.52 x 62.428 / 1
= 344.60 lb/ft³
hope this helps!
Answer:
133.34 g/moles
Explanation:
but to make life easy it could be 133.4 g/ moles as well
Answer:

Explanation:
Hello,
In this case, since you have both the final and initial volume for the titration procedure, clearly, the used volume is computed by the subtraction between them, since it accounts for the employed volume of the base, it turns out:

Best regards.