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Strike441 [17]
2 years ago
11

In a combustion chamber, ethane (c2h6) is burned at a rate of 9 kg/h with air that enters the combustion chamber at a rate of 17

6 kg/h. determine the percentage of excess air used during this process
Chemistry
1 answer:
nekit [7.7K]2 years ago
3 0

The percentage of excess air used during combustion process of ethane will be 37 %.

Burning, also known as combustion, would be a high-temperature highly exothermic chemical process that occurs when an oxidant, typically atmospheric oxygen, interacts with a fuel to generate oxidized, frequently gaseous products in a mixture known as smoke.

Calculation of percentage of air .

C_{2} H_{6} + (1-x)+a(O_{2} +3.76N_{2} )=bCO_{2}  + cH_{2} O + axO_{2}  + 3.76dN_{2} .

Mair=Mair/Rin

( MN)O_{2} + (MN)N_{2}÷ (MN)O_{2} + (MN)N_{2} +(MN)C_{2} H_{6} .

33 . 3.25(1-x) + 28 × 13.16(1-x) ÷ 33 × 3.25(1-x) + 28 × 13.16(1-x). + 30.1

= 176/176+8

X= 0.37

0.37 × 100

X= 37%

Therefore, the percentage of excess air used during combustion process of ethane will be 37 %.

To know more about combustion process

brainly.com/question/13153771

#SPJ4

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<h3>Explanation:</h3>

Given;

Mass of diprotic acid, H₂X =0.352 g

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Volume of the NaOH = 36.4 mL

We are required to calculate the molar mass of the acid.

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<h3>Step 1: Write the balanced equation fro the reaction;</h3>

The balanced equation for the reaction between the diprotic acid and NaOH will be;

H₂X(aq) + 2NaOH(aq) → Na₂X(aq) + 2H₂O(l)

<h3>Step 2: Determine the number of moles of NaOH used </h3>

Given the molarity and volume of NaOH we can calculate the number of moles;

Moles of NaOH = Molarity × Volume

                          = 0.150 M × 0.0364 L

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<h3>Step 3: Use the mole ratio to determine moles of the acid </h3>

From the equation;

1 mole of the acid reacts with 2 moles of NaOH

Therefore; H₂x : NaOH = 1 : 2

Moles of H₂x = 0.00546 moles ÷ 2

                      = 0.00273 moles

<h3>Step 4: Determine the molar mass of the acid.</h3>

Molar mass is the mass equivalent to 1 mole of a compound or element

From our calculations;

0.00273 moles = 0.352 g of the acid;

Therefore, mass in 1 mole ;

= 0.352 g ÷ 0.00273 moles

= 128.94 g/mol

Thus, the molar mass of the diprotic, H₂X is 128.94 g/mol

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