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EleoNora [17]
2 years ago
9

The Sloan Digital Sky Survey includes many thousands of galaxies in its spectroscopic catalogs. How are the distances to most of

these galaxies estimated
Physics
1 answer:
Katarina [22]2 years ago
3 0

The distances to the most of these galaxies estimated from their red shifts and the application of Hubble's Law.

<h3>What is Hubble's Law?</h3>

The discovery in physical cosmology that galaxies are travelling away from Earth at rates proportionate to their distance is known as Hubble's law, often referred to as the Hubble-Lemaître law or Lemaître's law. In other words, they are travelling away from Earth more quickly the more away they are. The redshift of the galaxies—a shift in the light they produce toward the red end of the visible spectrum—has been used to calculate their velocities.

The Sloan Digital Sky Survey includes many thousands of galaxies in its spectroscopic catalogs. The distances to the most of these galaxies estimated

from their red shifts and the application of Hubble's Lawh

to learn more about Hubble's law go to - brainly.com/question/3050512

#SPJ4

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A substance that contains only one kind of matter is known as a (n)
8090 [49]
I think the question is fishing for "element".
5 0
3 years ago
In a machining operation that approximates orthogonal cutting, the cutting tool has a rake angle =100 . The chip thickness ratio
Rudik [331]

Answer:

The percentage of the total energy dissipated into shear plane is 89.46%.

Explanation:

Given that,

Rake angle = 10°

Thickness ratio= 0.5

Cutting Force = 400 N

Thrust force = 200 N

Speed =3 m/s

Suppose the shear force is 345.21 N.

We need to calculate the shear plane angle

Using formula shear angle

\tan\phi=\dfrac{r\cos\alpha}{1-r\sin\alpha}

Put the value in to the formula

\tan\phi=\dfrac{0.5\cos10}{1-0.5\sin10}

\tan\phi=0.539

\phi=\tan^{-1}(0.539)

\phi=28.32^{\circ}

We need to calculate the shear velocity

Using formula of shear velocity

v_{2}=\dfrac{v\cos\alpha}{\cos(\phi-\alpha)}

Put the value into the formula

v_{2}=\dfrac{3\times\cos10}{\cos(28.32-10)}

v_{2}=3.11\ m/s

We need to calculate the percentage of the total energy dissipated into shear plane

Using formula of energy dissipated

\%d=\dfrac{P_{s}}{P}\times100

\%d=\dfrac{F_{s}\times v_{c}}{F_{c}\times v}\times100

Put the value into the formula

\%d=\dfrac{345.21\times3.11}{400\times3}\times100

d=89.46\%

Hence, The percentage of the total energy dissipated into shear plane is 89.46%.

6 0
3 years ago
A fish in an aquarium with flat sides looks out at a hungry cat. To the fish, does the distance to the cat appear to be less tha
lakkis [162]

Answer:

p = -q  

he distance is equal to the current distance, so the distance does not change

Explanation:

For this exercise we can solve it using the equation of the constructor

            1 / f = 1 / p + 1 / q

where f is the focal length, p the distance to the object and q the distance to the image

For a flat surface the radius is at infinity, therefore 1 / f = 0, which implies

          1 / p = - 1 / q

           p = -q

Therefore the distance is equal to the current distance, so the distance does not change

7 0
3 years ago
A ball rolling down a ramp accelerates from 0 m/s to 40 m/s in 10 seconds. What is its acceleration?
dmitriy555 [2]

Answer:

4

Explanation:

you have to divide the velocity by time so 40 divided by 10 and the answer should be 4

7 0
3 years ago
Read 2 more answers
A bungee jumper attains a speed of 30 m/s just as the bungee cord begins to stretch. If the period of stretch is 2 s while comin
Bogdan [553]

Answer:1.53g

Explanation:

average deceleration= ?

inial velocity: u=0

final velocity: v=30m/s

time: t=2seconds

The first law of kinematics :

v=u+at

find a the subject of the formula

a=v-u/ t

a=\frac{0-30} 2

a=-30/2

a=-15m/s^{2}

The deceleration about g(acceleration due to gravity) will be:

15/9.8

1.53g

4 0
3 years ago
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