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victus00 [196]
3 years ago
6

13. An object, travelling along a straight path, covers 35 m distance in 4 seconds. In next 6

Physics
2 answers:
dem82 [27]3 years ago
6 0

Answer:

(4) 8.5 m/s

Explanation:

Total distance = 35 + 50 = 85m

Total time = 4 + 6 = 10sec

average speed = total distance/ total time

ave. speed = 85/10 = 8.5 m/s

WARRIOR [948]3 years ago
5 0

Answer:

(4) 8.5 m/s

Explanation:

You add both the meters together and both the seconds together and then divide them both.

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13:9 because he starts back then runs slower
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Anya has 115 mangoes lauren has five times the the number of mangoes Anya has they put them together and sold them in the market
inessss [21]

$10,350 is the amount of money that has been collected mangoes are sold by Anya and Lauren at $15.

Number of mangoes of Anya's = 115 mangoes

Number of mangoes of Lauren's = 5 × 115 = 575 mangoes

Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has

= 115 + 575

= 690 mangoes

Amount each mango sold = $15

The total amount of money collected = Total number of mangoes × Amount each mango were sold

= 690 × 15

= $10,350

So, therefore, Anya and Lauren sold their total mangoes for $10,350.

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5 0
1 year ago
Suppose one organ in the organ system failed to work properly, How would the organ system be affected? Would it still be able to
scoray [572]

The organ system failing would affect the rest of the body. You would probablly not live long. The human anatomy is very important. It won work properly. It will affect the rest of your body and probably land you in the hospital. This is why one failing organ system can be fatal.

8 0
3 years ago
Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t square
Dahasolnce [82]

Answer:

a. Time=25seconds

b.distance=1041.67m

Explanation:

a.The equation for D in terms of m/s is \frac{250}{3}m/s after conversion.

To find when speed reaches 300km/hr=83.33m/s, we find D\prime and solve for t

D=\frac{5}{3}t^2\\D\prime=\frac{5}{3}(2t)=\frac{10}{3}t=\frac{250}{3}\\t=25sec

b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.

#To find distance travelled in that time , we substitute fort=25 in our distance equation:

D(25)=\frac{5}{3}(25)^2\\=1041.67m

Hence the distance of the plane before it gets airborne is 1041.67m

4 0
3 years ago
a closed tank is partially filled with glycerin. if the air pressure in the tank is 6 lb/in.2 and the depth of glycerin is 10 ft
vlabodo [156]

Answer:

<u><em>note:</em></u>

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