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victus00 [196]
3 years ago
6

13. An object, travelling along a straight path, covers 35 m distance in 4 seconds. In next 6

Physics
2 answers:
dem82 [27]3 years ago
6 0

Answer:

(4) 8.5 m/s

Explanation:

Total distance = 35 + 50 = 85m

Total time = 4 + 6 = 10sec

average speed = total distance/ total time

ave. speed = 85/10 = 8.5 m/s

WARRIOR [948]3 years ago
5 0

Answer:

(4) 8.5 m/s

Explanation:

You add both the meters together and both the seconds together and then divide them both.

You might be interested in
z jaka maksymalna predkoscia porusza sie przez krotka chwile rowerzysta jezeli dysponuje moca maksymalna 420w i przy predkosci z
qwelly [4]

Answer:

12 m/s

Explanation:

English Translation

At what maximum speed is the cyclist traveling for a short time if he has a maximum power of 420W and at this speed he must overcome the resistance 35N.

The Power, P, expended by a moving body with velocity, v, moving against a resistive force of F is given as

P = Fv

P = 420 W

F = 35 N

v = ?

420 = 35v

v = (420/35) = 12 m/s

In Polish/Po polsku

Moc P, wydana przez poruszające się ciało z prędkością v, poruszająca się przeciw sile oporu F, jest podana jako

P = Fv

P = 420 W

F = 35 N

v = ?

420 = 35v

v = (420/35) = 12 m/s

Hope this Helps!!!

Mam nadzieję że to pomoże!!!

6 0
3 years ago
An energy plant produces an output potential of 1500 kV and serves a city 143 km away. A high-voltage transmission line carries
jekas [21]

Answer:

2123.55 $/hr

Explanation:

Given parameters are:

V_{plant} = 1500 KV

L = 143 km

I = 500 A

\rho = 2.4 \Omega / km

So, we will find the voltage potential provided for the city as:

V_{wire} =IR = I\rho L = 1500*2.4*143 = 514.8 kV

V_{city} = V_{plant}- V_{wire} = 1500-514.8 = 985.2 kV

Then, we will find dissipated power because of the resistive loss on the transmission line as:

P = I^2R = I^2\rho L=500^2*2.4*143 = 8.58*10^7 W

Since the charge of plant is not given for electric energy, let's assume it randomly as x =  \frac{\dollar 0.081}{kW.hr}

Then, we will find the price of energy transmitted to the city as:

Cost = P * x = 8.58*10^7 * 0.081 * 0.001 = 6949.8 $/hr

To calculate money per hour saved by increasing the electric potential of the power plant:

Finally,

I_{new} = P/V_{new} = I/1.2\\P_{new} = I_{new}^2R_{wire}\\Cost = P_{new}/1.44=6949.8/1.44 = 4826.25 $/hr

The amount of money saved per hour = 6949.8 - 6949.8/1.44 = 2123.55 $/hr

Note: For different value of the price of energy, it just can be substituted in the equations above, and proper result can be found accordingly.

3 0
3 years ago
A rope attached to a load of 175 kg bricks Ilifts the bricks with a steady acceleration of 0.12.m/s^2 straight up. What is the t
andrew-mc [135]

Answer:

Tension, T = 1736 N

Explanation:

It is given that,

Mass of bricks, m = 175 kg

A rope is attached to a load of 175 kg bricks lifts the bricks with a steady acceleration of 0.12 m/s² in vertically upwards direction. let T is the tension in the rope. Using second equation of motion as :

T - mg = ma

T = ma + mg

T = m(a + g)

T = 175 kg ( 0.12 m/s² + 9.8 m/s² )

T = 1736 N

Hence, the tension in the wire is 1736 N.

4 0
3 years ago
Read 2 more answers
  URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you ha
Liono4ka [1.6K]

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

4 0
3 years ago
Balance the following chemical equations
IrinaVladis [17]

Answer:

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below

Always use the upper case for the first character in the element name and the lower case for the second character.

To enter an electron into a chemical equation use {-} or e

To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}. Example: Fe{3+} + I{-} =...

Substitute immutable groups in chemical compounds to avoid ambiguity. For instance equation C6H5C2H5 + O2 = C6H5OH + CO2...

Explanation:

4 0
4 years ago
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