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3 years ago

13. An object, travelling along a straight path, covers 35 m distance in 4 seconds. In next 6

Physics

2 answers:

dem82 [27]3 years ago

6 0

Answer:

(4) 8.5 m/s

Explanation:

Total distance = 35 + 50 = 85m

Total time = 4 + 6 = 10sec

average speed = total distance/ total time

ave. speed = 85/10 = 8.5 m/s

WARRIOR [948]3 years ago

5 0

Answer:

(4) 8.5 m/s

Explanation:

You add both the meters together and both the seconds together and then divide them both.

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What is radiation produces a wave full energy.

Alexeev081 [22]

Answer:

electromagnetic radiation hopefully

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2 years ago

A small mass is released from rest from the edge of a frictionless, hemispherical bowl. As the mass passes through the bottom of

Greeley [361]

Answer:

$a=2g$

Explanation:

Let the radius of the hemisphere is R. The mass is released from rest so the initial speed is equal to zero and acceleration is equal to the g.

By the Newton's 3rd equation,

$v^2=u^2+2as\\v^2=2gR\\v=\sqrt{2gR}$

Now, at the bottom hemisphere the centripetal acceleration will act on the mass and the direction of this force is towards center,

$a_c=\frac{v^2}{R}\\a_c=\frac{(\sqrt{2gR} )^2}{R}\\a_c=2g$

Hence, the acceleration on the bottom of the hemisphere is equal to the 2g.

4 0

3 years ago

Heeeelllllllpppp I need this right now

dem82 [27]

Static friction

hope this helps

7 0

3 years ago

Read 2 more answers

Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t

NemiM [27]

Answer:

their final velocity is 0.091 m/s

Explanation:

Given;

mass of the first train, m₁ = 138,000 kg

mass of the second train, m₂ = 123,000 kg

initial velocity of the first train, u₁ = 0.288 m/s

initial velocity of the seocnd train, u₂ = -0.131 m/s (opposite direction to the first)

Let their common final velocity after been coupled = v

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(138,000 x 0.288) + (-0.131 x 123,000) = v(138,000 + 123,000)

39,744 - 16,113 = v(261,000)

23,631 = v(261,000)

v = 23,631 / 261,000

v = 0.091 m/s

Therefore, their final velocity is 0.091 m/s

5 0

3 years ago

The coefficient of static friction between hard rubber and normal street pavement is about 0.90. On how steep a hill (maximum an

jok3333 [9.3K]

First thing to do is to draw the system described above. Then, write an equation for the forces present.

ΣF = Fg - Ff
0 = mgsin∅ - umgcos∅0 = gsin∅ - ugcos∅
u = tan∅
∅(max) = tan^-1 (u)

7 0

3 years ago

Read 2 more answers