Answer:
(a) 81.54 N
(b) 570.75 J
(c) - 570.75 J
(d) 0 J, 0 J
(e) 0 J
Explanation:
mass of crate, m = 32 kg
distance, s = 7 m
coefficient of friction = 0.26
(a) As it is moving with constant velocity so the force applied is equal to the friction force.
F = 0.26 x m x g = 0.26 x 32 x 9.8 = 81.54 N
(b) The work done on the crate
W = F x s = 81.54 x 7 = 570.75 J
(c) Work done by the friction
W' = - W = - 570.75 J
(d) Work done by the normal force
W'' = m g cos 90 = 0 J
Work done by the gravity
Wg = m g cos 90 = 0 J
(e) The total work done is
Wnet = W + W' + W'' + Wg = 570.75 - 570.75 + 0 = 0 J
- The potential difference between two locations in an electric circuit is measured using a voltmeter.
- If the electricity passes through the voltmeter it shows deflection.
<h3>What is the purpose of a voltmeter?</h3>
- A voltage meter, usually referred to as a voltmeter, is a device that measures the voltage, or potential difference, between two points in an electrical or electronic circuit.
- volts is the unit of voltmeter(volts, millivolts, kilovolts)
<h3>What is the explanation for the link between current and voltage?</h3>
- Ohm's law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.
<h3>What is ohm's law in circuit?</h3>
- V = IR, where V is voltage, I is current, and R is resistance, is known as Ohm's Law.
- If you know the voltage of the battery in the circuit and how much resistance is in the circuit, you may use Ohm's Law to identify properties of a circuit, such as how much current is flowing through it.
To learn more about current and voltage visit:
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Use this formula to find your answer...
Determine the frequency of a clock waveform whose period is 2us or (micro) and 0.75ms
frequency (f)=1/( Time period).
Frequency of 2 us clock =1/2*10^-6 =10^6/2 =500000Hz =500 kHz.
Frequency of 0..75ms clock =1/0.75*10^-3 =10^3/0.75 =1333.33Hz =1.33kHz.
Answer:
Pemain A
Explanation:
Mengingat data berikut;
Kecepatan pemain A = 12 m/s
Kecepatan pemain B = 36 km/h
Untuk menentukan siapa pelari tercepat di antara dua pemain;
Pertama-tama, kita harus mengubah kecepatan menjadi satuan standar pengukuran yang sama.
Jadi, mari kita gunakan pengukuran umum meter per detik.
Konversi:
36 km/h = (36 * 1000)/(60 * 60)
36 km/h = 36000/3600
36 km/h = 10 m/s
Kecepatan pemain B = 10 m/s
Oleh karena itu, dibandingkan dengan kecepatan pemain A; pemain A lebih cepat.
