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Valentin [98]
4 years ago
6

Заряди +10 нКл і +18нКл розташовані на відстані 12 см один від одного.Яка сила діятиме на заряд +2 нКл,який розміщений на прямій

,що з'єднує заряди на відстані 3 см від першого заряду С малюнком
Physics
1 answer:
ludmilkaskok [199]4 years ago
3 0
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A 140 g baseball is moving horizontally to the right at 35 mis when it is hit by the bat. the ball fl ies off to the le ft at 55
Anit [1.1K]

Answer:

J = 12.32kg*m/s

Explanation:

Assumptions: I'm assuming mis is m/s

Given: The baseball's mass is 140g, so convert to kg, 0.140kg. (Good rule of thumb, in physics convert grams to kilograms). It is initially traveling 35 m/s to the right.

When it hits the bat, it flies left with a velocity of 55 m/s at an angle of 25°. To reiterate:

mass = 0.140kg, Initial: 35m/s, Final: 55m/s at an angle of 25°

For this problem, we have to use the impulse equation, but before that lets break the velocity into components (It will be apparent towards the end):

The initial velocity is moving only in the horizontal direction, so:

v_{0x} = 35 m/s

The final velocity has an x and a y component:

v_{fx} = 55cos(25) = 49.84692829m/s\\v_{fy} = 55sin(25) = 23.2440044m/s

Now the equation for impulse is (dp is Δp, which is difference in momentum; dv is Δv, the difference in velocity; J is impulse):

J = dp= m*dv

To get Δv, we have to find the difference of velocity, that is why we broke it into components. I'm going to define right as positive and left as negative. After that, we find the velocity vector:

dv_{x} = (35-(-49.84692829)) = 84.84692829 m/s\\dv_{y} = (0-(23.2440044)) = -23.2440044 m/s\\dv = \sqrt{(84.84692829)^2+(-23.2440044)^2} = 87.97320604m/s

Finally, substitute into the equation

J = m*dv\\J = 0.140kg * 87.97320604m/s\\J = 12.31624885kg*m/s\\J = 12.32 kg*m/s

J = 12.32kg*m/s

8 0
3 years ago
In the formula used to solve problems related to the first law of thermodynamics, what does Q represent? A.internal energy
Blizzard [7]
B, heat, is the correct answer. Heat is represented by a capital q in thermodynamic equations.
7 0
3 years ago
Read 2 more answers
Un libro del peso di 12 N è in equilibrio su un tavolo. Sapendo che il coefficiente di attrito statico vale 0,5, la forza di att
Tanzania [10]

Answer:

60

Explanation:

Translation -

A book weighing 12 N is balanced on a table. Knowing that the static friction coefficient is 0.5, how much is the friction force worth?

Friction force is

f = u * n

f = 0.5 * 12N

f = 60

4 0
4 years ago
After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average
loris [4]

Answer:

0.4455 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

Total mass is

m=62\times 25+15\times 3+5\times 3+25\\\Rightarrow m=1635\ kg

Here the spring constant is not given so let us assume it as k=36000\ N/m

Here, the forces are balanced

mg=kx\\\Rightarrow 1635\times 9.81=36000\times x\\\Rightarrow x=\dfrac{1635\times 9.81}{36000}\\\Rightarrow x=0.4455\ m

The springs are compressed by 0.4455 m

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4 years ago
Ball A has a mass of 0.200 kilograms. Ball A, traveling at a velocity of 2 meters/second in the +x direction, hits a stationary
Rama09 [41]
B because is the same mass
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3 years ago
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