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saul85 [17]
1 year ago
11

The standard reduction potential for the conversion of Fe(III) to Fe(II) value is 0.77 V. Iron is a component of many of the ele

ctron carriers of the electron-transport chain, which implies it can have several different reduction potentials. How can this be accomplished
Chemistry
1 answer:
andre [41]1 year ago
3 0

The concept of Standard electrode potential can be used to accomplish this.

<h3><u>Standard Reduction Potential</u></h3>

The standard reduction potential belongs to the group of potentials known as standard electrodes or standard cells. The difference in voltage between the cathode and anode is known as the standard cell potential. . All of the standard potentials are determined using 1 M solutions, 1 atm, and 298 K.

The probability of reducing a species is known as its standard reduction potential. It is expressed as a reduction half reaction in writing. Below is an illustration where "A" stands for a generic element and "C" represents the charge.

<u>Standard Reduction Potential:</u>

A⁽⁺+Ce⁻→A

For example, copper's Standard Reduction Potential of  Eo=+0.340V)  is for this reaction:

Cu²⁺+2e⁻→ Cu

The standard reduction potential and the standard oxidation potential are quite similar. It is the propensity of a species to undergo oxidation under normal circumstances. Additionally, it is written as a half reaction.

To view more questions about potential, refer to:

brainly.com/question/14219427

#SPJ4

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AnswerIm telling your teacher "Ms.Byrd" your in 8th grade and go to berry middle?

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2 years ago
Calculate the standard emf for the following reaction:
krek1111 [17]
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l) 
</span><span>E = +1.47 
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<span>Br(l) + 2e- = 2Br- 
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We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
4 0
3 years ago
Write balanced equations that describe the following reactions. (Use the lowest possible coefficients. Use the pull-down boxes t
Gnesinka [82]

Answer :  The balanced chemical reaction will be:

HBrO_4(aq)+H_2O(l)\rightarrow H_3O^+(aq)+BrO_4^-(aq)

Explanation:

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

As we know that perbromic acid is considered a strong acid that means it will completely dissociate in water.

The balanced chemical reaction will be:

HBrO_4(aq)+H_2O(l)\rightarrow H_3O^+(aq)+BrO_4^-(aq)

8 0
2 years ago
Microwave radiation has a wavelength on the order of 1.0 cm. Calculate the frequency and the energy of a single photon of this r
denis23 [38]

Answer :

(1) The frequency of photon is, 3\times 10^{10}Hz

(2) The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

Explanation : Given,

Wavelength of photon = 1.0cm=0.01m     (1 m = 100 cm)

(1) Now we have to calculate the frequency of photon.

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of photon

\lambda = wavelength of photon

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get:

\nu=\frac{3\times 10^8m/s}{0.01m}

\nu=3\times 10^{10}s^{-1}=3\times 10^{10}Hz    (1Hz=1s^{-1})

The frequency of photon is, 3\times 10^{10}Hz

(2) Now we have to calculate the energy of photon.

Formula used :

E=h\times \nu

where,

\nu = frequency of photon

h = Planck's constant = 6.626\times 10^{-34}Js

Now put all the given values in the above formula, we get:

E=(6.626\times 10^{-34}Js)\times (3\times 10^{10}s^{-1})

E=1.988\times 10^{-23}J/photon

The energy of a single photon of this radiation is 1.988\times 10^{-23}J/photon

(3) Now we have to calculate the energy in J/mol.

E=1.988\times 10^{-23}J/photon

E=(1.988\times 10^{-23}J/photon)\times (6.022\times 10^{23}photon/mol)

E=11.97J/mol

The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol

3 0
3 years ago
Read 2 more answers
How many significant figures are in 1.00 L
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Answer:

3 significant numbers

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