1. a 0. 338-g sample of antimony was completely reacted with 0. 295 g of chlorine gas to form antimony chloride. determine the e
1 answer:
The empirical formula of the antimony chloride is .
Chemical formulas for compounds that simply specify the proportions of the elements they contain rather than the exact number or arrangement of atoms are known as empirical formulas. The element in the compound with the lowest whole number ratio would be this one.
Data obtained from the question
Antimony (Sb) = 0.338 g
Chlorine (Cl) = 0.295 g
Divide by their molar mass.
Sb = 0.338 / 122 = 0.0028
Cl = 0.295 / 35.5 = 0.0083
Divide by the smallest.
Sb = 0.0028 / 0.0028 = 1
Cl = 0.0083 / 0.0028 = 3
Thus, the empirical formula of the compound is SbCl₃.
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Hi there,
for this question we have:
Signal 2.0 MHz = Emitted so we can call it
and we need the Reflected =
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz =
so we have:
- =
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz =
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=>
= (lambda)(
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the is equal to 1532 m/s :)))
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day
for this question we have:
Signal 2.0 MHz = Emitted so we can call it
and we need the Reflected =
In this question, we have a source which goes to the heart and a reflected which comes back from the heart and we need the speed of the reflected.
So you should know that the speed of reflected is lower than the source(Emitted).
we also know: ΔBeat frequency(max) = 560 Hz =
so we have:
so frequency of Reflected is:
2.0 × 10^6 Hz - 560 Hz = 1.99 × 10^6 Hz =
now you know that Lambda = v/f
so if we find the lambda with our Emitted then we can find v with the Reflected:
Lambda = 1540(m/s) / 2.0 × 10^6 Hz = 7.7 × 10^-4 m
=>
=> 7.7 × 10^-4m (1.99 × 10^6Hz) = 1532 m/s
so the
This question is solved by two top teachers as fast as they could :))
I hope this is helpful
have a nice day