1. a 0. 338-g sample of antimony was completely reacted with 0. 295 g of chlorine gas to form antimony chloride. determine the e
1 answer:
The empirical formula of the antimony chloride is .
Chemical formulas for compounds that simply specify the proportions of the elements they contain rather than the exact number or arrangement of atoms are known as empirical formulas. The element in the compound with the lowest whole number ratio would be this one.
Data obtained from the question
Antimony (Sb) = 0.338 g
Chlorine (Cl) = 0.295 g
Divide by their molar mass.
Sb = 0.338 / 122 = 0.0028
Cl = 0.295 / 35.5 = 0.0083
Divide by the smallest.
Sb = 0.0028 / 0.0028 = 1
Cl = 0.0083 / 0.0028 = 3
Thus, the empirical formula of the compound is SbCl₃.
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There you go, hope that helps.
