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Nikolay [14]
3 years ago
5

PLEASE HELP! 2ND TIME I ASKED THIS!!!

Physics
1 answer:
Goshia [24]3 years ago
4 0

The train is moving at 50 m/s and Emma is walking down the aisle with 1 m/s speed in the same direction of train. The relative velocity of Emma with respect to other passengers pf the train would be 1 m/s. This is because, the train is not moving relative to them and only emma is moving at 1 m/s. If a person observes from outside, Emma would have (50 +1) m/s = 51 m/s velocity.

relative velocity when two objects are moving in same direction as oberved from outside observer:

v_{ab}=v_a+v_b

relative velocity when two objects are moving in the opposite directionas oberved from outside observer:

v_{ab}=v_a-v_b

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Find the force between charges of +10.0 C and -50.0 C located 20.0 cm apart
polet [3.4K]

The magnitude of the electrostatic force between the two charges is 1.12\cdot 10^{14} N

Explanation:

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, we have:

q_1 = +10.0 C

q_2 = -50.0 C

r = 20.0 cm = 0.20 m

Therefore, the force between the charges is

F=(8.99\cdot 10^9) \frac{(10)(-50)}{(0.20)^2}=-1.12\cdot 10^{14} N

where the negative sign means that the force is attractive, since the two charges have opposite sign.

Learn more about electrostatic force here:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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