VTheStampy is this right and what do I do next?

A box is given a push so that it slides across the floor. How far will it go, given that the coefficient of kinetic friction is

IRINA_888 [86]

Answer:

s=4.44 m

Explanation:

Given that

Coefficient of the kinetic friction ,μ = 0.13

Initial velocity ,u= 3.4 m/s

Final velocity of the box ,v= 0 m/s

The acceleration due to friction force

a= - μ g

Now by putting the values in the above equation

a= - 0.13 x 10 ( take g= 10 m/s²)

a= - 1.3 m/s²

We know that

v²= u ² + 2 a s

s=distance

a=acceleration

v=final speed

u=initial speed

Now by putting the values in the above equation

0²= 3.4² - 2 x 1.3 x s

$s=\dfrac{3.4^2}{2\times 1.3}\ m$

s=4.44 m

The distance cover by box will be 4.44 m.

6 0

3 years ago

A 2.50 gram rectangular object has measurements of 22.0 mm, 13.5 mm, and 12.5 mm. what is the objectâs density in units of g/ml?

navik [9.2K]

<span>To calculate the density, we must first calculate the volume of the object. For a rectangle, the volume is equal to V=l*w*h. In this case, V=22*13.5*12.5=3712.5 mm^3. Next we have to convert the mm^3 to mL using the conversion factor of 1 mm^3=.001 mL. To get mL, we set up the expression 3712.5 mm^3 * (.001mL/1mm^3) = 3.7125 mL. Finally, to get the density, we know density is mass over volume, so we set the expression p=m/V=2.5g/3.7125mL=.6734 which rounded to 3 significant figures is .673. The answer will be .673</span>

8 0

3 years ago

A pendulum has a mass of 0.060 kg swinging at a small angle from a light string, with a period of 1.4 s. What is the length of t

jok3333 [9.3K]

Answer:

0.5 m

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 0.060 kg

Period (T) = 1.4 s

Lenght (L) =?

NOTE:

1. Acceleration due to gravity (g) = 10 m/s²

2. Pi (π) = 3.14

The length of the pendulum can be obtained as follow:

T = 2π√(L/g)

1.4 = 2 × 3.14 × √(L/10)

1.4 = 6.28 × √(L/10)

Divide both side by 6.28

1.4 / 6.28 = √(L/10)

Take the square of both side

(1.4 / 6.28)² = L/10

Cross multiply

L = 10 × (1.4 / 6.28)²

L = 0.5 m

Therefore, the length of the pendulum is 0.5 m

4 0

3 years ago

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Marvin uses a long copper wire with resistivity 1.68 x 10^-8 Ω⋅m and diameter 1.00 x 10^−3 m to create a solenoid that has a 3

Mazyrski [523]

Answer with Explanation:

We are given that

Resistivity of copper wire= $\rh0=1.68\times 10^{-8}\Omega m$

Diameter=d= $1.00\times 10^{-3} m$

Radius of copper wire= $r=\frac{d}{2}=\frac{1}{2}\times 10^{-3} m$

Radius of solenoid=r' $=3 cm=3\times 10^{-2} m$

1 m=100 cm

a.Length of wire=l=11.3 m

Area of wire=A= $\pi r^2$

Where $\pi=3.14$

A= $3.14\times (\frac{1}{2}\times 10^{-3})^2$

Resistance, R= $\rho \frac{l}{A}$

Using the formula

$R=1.68\times 10^{-8}\times\frac{11.3}{3.14\times (\frac{1}{2}\times 10^{-3})^2}$

$R=0.24\Omega$

B.Length of solenoid= $2\pi r'=2\times 3.14\times 3\times 10^{-2}=0.188$ m

Number of turns= $n_0=\frac{l}{2\pi r'}=\frac{11.3}{0.188}$

$n_0$ =60

C.Potential difference,V=3 V

Current,I= $\frac{V}{R}$

I= $\frac{3}{0.24}=12.5 A$

D.Total length =0.1 m

Number of turns per unit length,n= $\frac{60}{0.1}=600$

Magnetic field along central axis inside of the solenoid,B= $\mu_0 nI$

$B=4\pi\times 10^{-7}\times 12.5\times 600=9.42\times 10^{-3} T$

4 0

3 years ago

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Which is the satellite Terra able to do?

11111nata11111 [884]

The Terra satellite was sent to space on <span>December 18, 1999 and is still there in 2016. The satellite is able to monitor volcanic eruptions on Earth. The correct answer is D. </span>

7 0

3 years ago

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