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laila [671]
2 years ago
11

A bus travelling at 30m/s along a straight road passes throu a stationary taxi cab.the can begins to move 5seconds later within

a uniform acceleration of 2metres per seconds square in the same direction as the bus.1.calculate the time taken by the cab to meet the bus.2.distance the cab has travelled to catch-up with the bus
Physics
1 answer:
goldenfox [79]2 years ago
3 0

(1) The time taken by the cab to meet the bus is 18.96 seconds.

(2) The distance the cab has travelled to catch-up with the bus is 718.96 m.

<h3>Distance between the bus and the cab</h3>

The distance between the bus and the cab when the cab begins to move is calculated as follows;

D = speed x time

D = 30 m/s x 5 s

D = 150 m

<h3>Velocity of the cab</h3>

The velocity of the cab when it begins to move is calculated as follows;

v = at

(v - 30)t = D

(at - 30)t = 150

(2t - 30)t = 150

2t² - 30t = 150

2t² - 30t - 150 = 0

solve the quadratic equation using formula method

t = 18.96 seconds

<h3>Distance traveled by the cab</h3>

D =  vt

D = 2t²

D = 2(18.96²)

D = 718.96 m

Thus, the time taken by the cab to meet the bus is 18.96 seconds. The distance the cab has travelled to catch-up with the bus is 718.96 m.

Learn more about distance here: brainly.com/question/2854969

#SPJ1

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