The formula for velocity vf = vi + at
First list your given information
2m/s Is your initial velocity (vi)
6m/s is you final velocity (vf)
2 seconds is your time (t)
Since you want the a for acceleration get a by itself
a = (vf-vi)/t
So a= (6-2)/2
a= 4/2
a=2
Now units
the units for acceleration are m/s
2m/s
Answer:
It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.
Step-by-step explanation:
Using the simultaneous equation concept, let A denote Andy and B be Brian
Andy and Brian can mow the lawn for 1212minutes i.e A+B = 1212..eqn 1
If Brian would mow the lawn by himself in 1010 minutes more than it would take Andy, this means B=1010A...eqn 2.
Substituting eqn 2 into eqn 1
Equation 1 becomes
A+1010A=1212
1011A=1212
A=1212/1011
A=1.198
B = 1010×1.198
B=1,209.98
Therefore, It will take Andy 1.198minutes to mow the lawn and it will take Brian 1,209.98minutes to mow the same lawn.
Carbon capture is the safest way to capture emission.
<u>Explanation:</u>
Emission of green house gases is one of the most lurking threat above humans. So one of the best ways to reduce emission is to capture the gases like carbon di-oxide or carbon monoxide, nitrous oxide etc. So mostly, the carbon di-oxide gas which is produced as waste is captured using adsorption, absorption, chemical looping etc.
In this method, they are captured from high source points like cement factory etc and then stored in a secluded region. Thus, the adsorption of these gases and then storing them in secluded region is the best option for capturing emission.
Answer: the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h
Explanation:
1) The motion of an object under the action of gravity, when air resistance is neglected is called projectile motion. The path is a curve with the form of a parabola.
2) The equations that rule that motion are:
- Horizontal speed:
- Vx = Vox = constant.
- In this case it is the same horizontal speed of the plane at the moment when the object was proyected. Vx = 429 km/h.
Vy = Voy + gt
d = yo - Voy×t - gt² / 2
Vy² = Voy² - 2gd
- Since, you know Voy =0, g = 9.81 m/s², and d = 500m, you can use the last equation, leading to:
Vy² = 2(9.81m/s²)(500m) = 9,810 m²/s² ⇒ Vy = √(9,810 m²/s²) = 99 m/s
3) As per definition the average velocity is displacement / time, so you need to find the time to reach the ground.
- You can use the formula Vy = Voy + gt
- Clear t: t = (Vy - Voy) / g = (99 m/s - 0) / 9.81 m/s = 10.1s
- Average vertical velocity = 500 m / 10.1s = 49.5 m/s.
- You can convert to km/h: 49.5 m/s × 1km/1,000m × 3600s/h = 178 km/h
4) Conclusion: the average vertical component of velocity between the object's release and its striking the ground is 49.5 m/s or 178 km/h
