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zheka24 [161]
3 years ago
10

What cell organelle is necessary for cellular respiration

Physics
2 answers:
podryga [215]3 years ago
4 0
It is the cytoplasm.
jekas [21]3 years ago
3 0
The cell organelle that is necessary for cellular respiration is the mitochondria.
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A small boat is moving at a velocity of 3.35m/s when it is accelerated by a river current perpendicular to the initial direction
mr_godi [17]

Answer:

 v =7.1 m/s

Explanation:

Given that

u = 3.35 m/s

t= 5 s

a= 0.75 m/s²

The final velocity = v

We know v = u +at

v=final velocity

u=initial velocity

Now by putting the values in the above equation

v = 3.35 + 0.75 x 5 m/s

v =7.1 m/s

Therefore the final velocity will be 7.1 m/s

7 0
3 years ago
The astronomer who first worked out the mathematical description of black hole event horizons was?
vovangra [49]

Karl Schwarzschild devised the first general relativity model that would adequately describe a black hole in 1916.

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4 0
2 years ago
What happens with alpha, beta, and gamma radiation?
tresset_1 [31]
I'm sorry but I don't really understand the question. What is the quest actually asking???
4 0
3 years ago
The force of gravity on Jupiter is much stronger than the force of gravity on earth what is the answer?
Pachacha [2.7K]

This would be true. On Jupiter you would weigh 234 pounds if you were 100 pounds on Earth.

7 0
3 years ago
Read 2 more answers
If the magnitude of the magnetic field is 6.50 mT at a distance of 12.8 cm from a long straight current carrying wire, what is t
Lunna [17]

Answer: magnitude of the magnetic field at a distance of 19.4 cm from the wire=4.29mT

Explanation:

According to  Biot-Savart law, A magnetic field generated by a current  carrying wire at a distance is represented as

B=μ₀I/ 2πr

B = magnetic field intensity 1000 mT =1T, 6.50mT = 6.50 X 10^-3T

 μ₀ =permeability of free space  4π × 10−7 H/m

I = current intensity

r = radius, 100cm = 1m, 12.8 cm= 12.8 x 10^-2m

6.50 X 10^-3 =  μ₀ x I/ 2 π X 12.8 X 10^-2

I =6.50  X 10 ^-3 X 2π  X  X 12.8 X 10^-2/  4π × 10−7 H/m

I= 4160 A

when the magnetic field is at 19.4 cm from the wire

B=μ₀I/ 2πr

= 4π × 10−7 H/m x4160/ 2π x 19.4 x 10^-2

=0.004288

= 4.29x 10 ^-3T

= 4.29mT

7 0
3 years ago
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