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Xelga [282]
3 years ago
6

A mover uses a ramp to push a stereo into the moving van. The ramp is 3 meters long and 1.5 meters high. What is the ima of this

ramp?
Physics
1 answer:
densk [106]3 years ago
4 0

Mechanical advantage<span> <span>is a measure of the force amplification achieved by using a tool, </span>mechanicaldevice or machine system. Ideally, the device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force. The model for this is the law of the lever. So the ima is 3/1.5 = 2</span>

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Two competing models attempt to explain the motions and changing brightness of the planets: Ptolemy's geocentric model and Coper
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Answer:

A. Geocentric: This model is Earth Centered . Retrograde motion is explained by epicycles .

B. Heliocentric: This model is Sun centered.  Retrograde motion is explained by the orbital speeds of planets

C. Both geocentric and heliocentric: Epicycles and deferents help explain planetary motion . Planets move in circular orbits and with uniform motion . The brightness of a planet increases when the planet is closest to Earth.

Explanation:

The principle of the Ptolemy's geocentric model was developed on the assumption that the center of the universe is the Earth. On the other hand, the principle of the Copernicus' heliocentric model was based on the assumption that the center of the universe is the sun. However, both models have a common ideology on uniform circular motion and epicycles.

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Answer:

F = 2,894 N

Explanation:

For this exercise let's use Newton's second law

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Let's replace

     F = m w² r

The radius r and the length of the rope is related

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Let's replace

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Let's reduce the magnitudes to the SI system

     m = 101.7 g (1 kg / 1000g) = 0.1017 kg

      θ = 5 rev (2π rad / rev) = 31,416 rad

     w =  θ / t

     w = 31.416 / 5.1

     w = 6.16 rad / s

     F = 0.1017 6.16² 0.75 cos  θ

     F = 2,894 cos  θ

The maximum value of F is for  θ equal to zero

     F = 2,894 N

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To be accurate, it must be able to make measurements that are close to the actual value.

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I hope this helps!
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