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suter [353]
3 years ago
15

According to periodic trend, which of the following most likely has the highest ionization energy?

Chemistry
2 answers:
WINSTONCH [101]3 years ago
8 0
Ionization energy increases across the period so Ar
baherus [9]3 years ago
7 0
In my opinion, it is Ar (Argon)
Because as we move from left to right in a period, the value of ionization energy increases and Argon occupies the left most side in the respective period of the Periodic Table
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X:5.8g=16:(23+1+12+3*16)
x:5.=16:84 
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4 0
3 years ago
In order to keep the bench from conducting heat, Shane could build it out of _______.
lara31 [8.8K]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ In order to keep the bench from conducting heat, Shane could build it out of wood. Wood doesn't conduct heat so this would work best for Shane.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

8 0
3 years ago
Read 2 more answers
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3 0
3 years ago
For which of the following aqueous solutions would one expect to have the largest van’t Hoff factor (i)? a. 0.050 m NaCl b. 0.50
ira [324]

Answer:

The van't hoff factor of 0.500m K₂SO₄ will be highest.

Explanation:

Van't Hoff factor was introduced for better understanding of colligative property of a solution.

By definition it is the ratio of actual number of particles or ions or associated molecules formed when a solute is dissolved to the number of particles expected from the mass dissolved.

a) For NaCl the van't Hoff factor is 2

b) For K₂SO₄ the van't Hoff factor is 3 [it will dissociate to give three ions one sulfate ion and two potassium ions]

Out of 0.500m and 0.050m K₂SO₄, the van't hoff factor of 0.500m K₂SO₄ will be more.

c) The van't Hoff factor for glucose is one as it is a non electrolyte and will not dissociate.

7 0
3 years ago
Identify the double displacement reaction. 3Pb 2h 3PO 4 ⟶ 3H 2 Pb 3(PO 4) 2 2NO 2 ⟶ 2O 2 N 2 2NaBr Ca(OH) 2 ⟶ CaBr 2 2NaOH 2NH 3
IRISSAK [1]

Reaction 3 is the double displacement reaction.

Double displacement reaction occurs when the negatively and the positively charged ions of the compounds interchange their position when the new compound in the product is formed.

<h3>Which is a double displacement reaction?</h3>

In the <u>first reaction</u>, the element lead (Pb) is not an ion and no exchange of the cations or the anions occurs hence it is not a double displacement reaction.

In the <u>second reaction</u>, one compound is getting split into two new compounds and is a decomposition reaction.

In the <u>third reaction</u>,  \rm Br^{-} in \rm 2NaBr and \rm (OH)_{2} in \rm Ca(OH)_{2} are anions and cations and exchanges their places to produce two new compounds  \rm CaBr_{2} + 2NaOH.

In the <u>fourth reaction</u>, a single compound is generated as the result of the combination reaction and hence, it is not the double displacement reaction.

Therefore, \rm 2NaBr + Ca(OH)_{2} \rightarrow CaBr_{2} + 2NaOH is the double displacement reaction.

Learn more about double displacement reaction here:

brainly.com/question/10091171

3 0
2 years ago
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