To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.
Gravitational potential energy can be defined as
![PE = -\frac{GMm}{R}](https://tex.z-dn.net/?f=PE%20%3D%20-%5Cfrac%7BGMm%7D%7BR%7D)
As M=m, then
![PE = -\frac{Gm^2}{R}](https://tex.z-dn.net/?f=PE%20%3D%20-%5Cfrac%7BGm%5E2%7D%7BR%7D)
Where,
m = Mass
G =Gravitational Universal Constant
R = Distance /Radius
PART A) As half its initial value is u'=2u, then
![U = -\frac{2Gm^2}{R}](https://tex.z-dn.net/?f=U%20%3D%20-%5Cfrac%7B2Gm%5E2%7D%7BR%7D)
![dU = -\frac{2Gm^2}{R}](https://tex.z-dn.net/?f=dU%20%3D%20-%5Cfrac%7B2Gm%5E2%7D%7BR%7D)
![dKE = -dU](https://tex.z-dn.net/?f=dKE%20%3D%20-dU)
Therefore replacing we have that,
![\frac{1}{2}mv^2 =\frac{Gm^2}{2R}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%5Cfrac%7BGm%5E2%7D%7B2R%7D)
Re-arrange to find v,
![v= \sqrt{\frac{Gm}{R}}](https://tex.z-dn.net/?f=v%3D%20%5Csqrt%7B%5Cfrac%7BGm%7D%7BR%7D%7D)
![v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B%5Cfrac%7B6.67%2A10%5E%7B-11%7D%2A1%2A10%5E%7B28%7D%7D%7B1%2A10%5E%7B12%7D%7D%7D)
![v = 816.7m/s](https://tex.z-dn.net/?f=v%20%3D%20816.7m%2Fs)
Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s
PART B) With a final separation distance of 2r, we have that
![2r = 2*10^3m](https://tex.z-dn.net/?f=2r%20%3D%202%2A10%5E3m)
Therefore
![dU = Gm^2(\frac{1}{R}-\frac{1}{2r})](https://tex.z-dn.net/?f=dU%20%3D%20Gm%5E2%28%5Cfrac%7B1%7D%7BR%7D-%5Cfrac%7B1%7D%7B2r%7D%29)
![v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7BGm%28%5Cfrac%7B1%7D%7B2r%7D-%5Cfrac%7B1%7D%7BR%7D%29%7D)
![v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B6.67%2A10%5E%7B-11%7D%2A10%5E%7B28%7D%28%5Cfrac%7B1%7D%7B2%2A10%5E3%7D-%5Cfrac%7B1%7D%7B10%5E%7B12%7D%7D%29%7D)
![v = 1.83*10^7m/s](https://tex.z-dn.net/?f=v%20%3D%201.83%2A10%5E7m%2Fs)
Therefore the velocity when they are about to collide is ![1.83*10^7m/s](https://tex.z-dn.net/?f=1.83%2A10%5E7m%2Fs)
1) Frequency: ![3.29\cdot 10^{15}Hz](https://tex.z-dn.net/?f=3.29%5Ccdot%2010%5E%7B15%7DHz)
the energy of the photon absorbed must be equal to the ionization enegy of the atom, which is
![E=2.18 aJ=2.18\cdot 10^{-18} J](https://tex.z-dn.net/?f=E%3D2.18%20aJ%3D2.18%5Ccdot%2010%5E%7B-18%7D%20J)
The energy of a photon is given by
![E=hf](https://tex.z-dn.net/?f=E%3Dhf)
where
is the Planck's constant. By using the energy written above and by re-arranging thsi formula, we can calculate the frequency of the photon:
![f=\frac{E}{h}=\frac{2.18\cdot 10^{-18} J}{6.63\cdot 10^{-34} Js}=3.29\cdot 10^{15} Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7BE%7D%7Bh%7D%3D%5Cfrac%7B2.18%5Ccdot%2010%5E%7B-18%7D%20J%7D%7B6.63%5Ccdot%2010%5E%7B-34%7D%20Js%7D%3D3.29%5Ccdot%2010%5E%7B15%7D%20Hz)
2) Wavelength: 91.2 nm
The wavelength of the photon can be found from its frequency, by using the following relationship:
![\lambda=\frac{c}{f}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bc%7D%7Bf%7D)
where
is the speed of light and f is the frequency. Substituting the frequency, we find
![\lambda=\frac{3\cdot 10^8 m/s}{3.29\cdot 10^{15}Hz}=9.12\cdot 10^{-8} m=91.2 nm](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B3%5Ccdot%2010%5E8%20m%2Fs%7D%7B3.29%5Ccdot%2010%5E%7B15%7DHz%7D%3D9.12%5Ccdot%2010%5E%7B-8%7D%20m%3D91.2%20nm)
Answer:
If the canoe heads upstream the speed is zero. And directly across the river is 8.48 [km/h] towards southeast
Explanation:
When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:
Vr = velocity of the river = 6[km/h}
Vc = velocity of the canoe = -6 [km/h]
We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.
Vt = Vr + Vc = 6 - 6 = 0 [km/h]
For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.
So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).
Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:
![Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]](https://tex.z-dn.net/?f=Vt%20%3D%20%5Csqrt%7B%286%29%5E%7B2%7D%20%2B%28-6%29%5E%7B2%7D%20%7D%20%5C%5CVt%3D8.48%5Bkm%2Fh%5D)
Answer:
What is sludge dumping? Sludge is the solid waste in raw sewage. Sludge dumping is discharging that waste into the ocean.
Explanation:
Answer:
To create an electric potential difference between the ends of the conductor.
Explanation:
For current to flow, there must exist an electric potential difference between the ends of the conductor. This PD is provided by the electromotive force stored within the battery. Unless there is a connection between the terminals no PD will exist between the terminals.