Answer:
![F_{sprinter}=110.4N](https://tex.z-dn.net/?f=F_%7Bsprinter%7D%3D110.4N)
Explanation:
Given data
Mass m=67.0 kg
Final Speed vf=8.00 m/s
Initial Speed vi=2.00 m/s
Distance d=25.0 m
Force F=30.0 N
From work-energy theorem we know that the work done equals the change in kinetic energy
W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²
And
![W=F_{total}.d](https://tex.z-dn.net/?f=W%3DF_%7Btotal%7D.d)
So
![W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N](https://tex.z-dn.net/?f=W%3D1%2F2mv_%7Bf%7D%5E2-1%2F2mv_%7Bi%7D%5E2%5C%5CF_%7Btotal%7D%3D%5Cfrac%7B1%2F2mv_%7Bf%7D%5E2-1%2F2mv_%7Bi%7D%5E2%7D%7Bd%7D%20%5C%5CF_%7Btotal%7D%3D%5Cfrac%7B1%2F2%2867.0kg%29%288.00m%2Fs%29%5E2-1%2F2%2867.0kg%29%282.00m%2Fs%29%5E2%7D%7B25.0m%7D%20%5C%5CF_%7Btotal%7D%3D80.4N)
and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N
So
The work that is required to increase the speed to 16 knots is 14,176.47 Joules
If a catamaran with a mass of 5.44×10^3 kg is moving at 12 knots, hence;
5.44×10^3 kg = 12 knots
For an increased speed to 16knots, we will have:
x = 16knots
Divide both expressions
![\frac{5.44 \times 10^3}{x} = \frac{12}{16}\\12x = 16 \times 5.44 \times 10^3\\x = 7.23\times 10^3kg\\](https://tex.z-dn.net/?f=%5Cfrac%7B5.44%20%5Ctimes%2010%5E3%7D%7Bx%7D%20%3D%20%5Cfrac%7B12%7D%7B16%7D%5C%5C12x%20%3D%2016%20%5Ctimes%205.44%20%5Ctimes%2010%5E3%5C%5Cx%20%3D%207.23%5Ctimes%2010%5E3kg%5C%5C)
To get the required work done, we will divide the mass by the speed of one knot to have:
![w=\frac{7230}{0.51}\\w= 14,176.47Joules](https://tex.z-dn.net/?f=w%3D%5Cfrac%7B7230%7D%7B0.51%7D%5C%5Cw%3D%2014%2C176.47Joules)
Hence the work that is required to increase the speed to 16 knots is 14,176.47 Joules
Learn more here: brainly.com/question/25573786
Answer:
a = 0.8 m/s^2
Explanation:
Force equation: F = ma
F = ma -> a = F/m = 2.8*10^3 N / 3.5*10^3 kg = 0.8 m/s^2
The wavelengths of radio waves are much "Longer" than the wavelength of microwaves therefore, radio waves carry much "Lower" <span>energy than a microwave.
Hope this helps!</span>
Answer:
2.75 m/s^2
Explanation:
The airplane's acceleration on the runway was 2.75 m/s^2
We can find the acceleration by using the equation: a = (v-u)/t
where a is acceleration, v is final velocity, u is initial velocity, and t is time.
In this case, v is 71 m/s, u is 0 m/s, and t is 26.1 s Therefore: a = (71-0)/26.1
a = 2.75 m/s^2