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1 year ago

Question 9 of 10

1 answer:

5 0

A atomic neutron particle that is attracting another atomic neutron is an example of the strong nuclear force acting in an atom (Option B).

<h3>What are nuclear forces?</h3>

The expression 'nuclear forces' makes reference to the attraction between different subatomic particles in a given nucleus of a particular atom, which represents the strongest force in the universe.

Subatomic particles include positively charged particles (i.e., protons), neutrally charged particles called neutrons, and electrically negative charged particles called electrons (e-).

In conclusion, a atomic neutron particle that is attracting another atomic neutron is an example of the strong nuclear force acting in an atom (Option B).

Learn more about nuclear forces here:

brainly.com/question/16959709

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A 5 kg ball is sitting on the floor without moving. What is the momentum of the ball?

natita [175]

Answer:

The ball has no momentum

Explanation:

The given parameters are;

The mass of the ball = 5 kg

The velocity of the ball = 0 (The ball is sitting on the floor without moving)

The momentum of the ball = The mass of the ball × Velocity of the ball

Therefore, the momentum of the ball = 5 kg × 0 m/s = 0

The momentum of the ball is zero, the ball has no momentum.

5 0

2 years ago

If the ball shown in the figure lands in 0.5 s, about what height was it thrown from?

Ede4ka [16]

Answer: 1.22 m

Explanation:

The equation of motion in this situation is:

$y=y_{o}+V_{oy}t-\frac{g}{2}t^{2}$ (1)

Where:

$y=0$ is the final height of the ball

$y_{o}=h$ is the initial height of the ball

$V_{oy}=V_{o}sin(0\°)=0$ is the vertical component of the initial velocity (assuming the ball was thrown vertically and there is no horizontal velocity)

$t=0.5 s$ is the time at which the ball lands

$g=9.8 m/s^{2}$ is the acceleration due gravity

So, with these conditions the equation is rewritten as:

$h=\frac{g}{2}t^{2}$ (2)

$h=\frac{9.8 m/s^{2}}{2}(0.5 s)^{2}$ (3)

Finally:

$h=1.22 m$

4 0

3 years ago

A rocket is launched from the launch pad at a speed of 700 km/hr.

Juliette [100K]

Answer:

Explanation:

Vm = Δs/Δt

700km/h = Δs/1.5h

700 = Δs/1.5

$\frac{700}{1} = \frac{S}{1.5}$

S = 700 x 1.5

S = 1050 Km

*(S = Δs)

Answer: The rocket will have traveled 1050 Km

Hope this help ☺

5 0

3 years ago

Provide two ways that objects can become charged

kap26 [50]

Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

8 0

3 years ago

What is the relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum? As t

Elanso [62]

<u>Explanation</u>

The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.

STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE

WAVE NUMBER SINGLE>DOUBLE>TRIPLE

wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).

8 0

3 years ago