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Dmitriy789 [7]
3 years ago
8

. Two identical vehicles traveling at the same speed are made to collide with barriers in an insurance company collision test. T

he first vehicle collides with a concrete barrier, and stops in a time of approximately 0.1 s. The second vehicle collides with a collapsible barrier, and comes to rest in about 1 second. Which object is subject to a larger force
Physics
1 answer:
Serggg [28]3 years ago
5 0

Answer:

F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

Explanation:

For this exercise let's use the relationship between momentum and momentum.

         I = F t = Δp

in this case the final velocity is zero

        F t = 0 -m v₀

        F = m v₀ / t

in order to answer the question we must assume that the two vehicles have the same mass and speed

concrete barrier

        F₁ = -p₀ / 0.1

        F₁ = - 10 p₀

barrier collapses

         F₂ = -p₀ / 1

let's look for the relationship of the forces

        F₁ / F₂ = 10

therefore the first out is 10 times greater than the second barrier

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Some of the frequency that cannot be produced by the string includes 400Hz, 500Hz 650Hz etc...

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Harmonics in strings are defined as the integral multiples of its fundamental frequency. This multiples are in arithmetic progression.

For example if Fo is the fundamental frequency of the string, the harmonics will be 2fo, 3fo, 4fo, 5fo... etc

If the string produces a fundamental frequency of 150Hz, some of the harmonics produced by the string will be 300Hz, 450Hz, 600Hz, 750Hz... etc

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. A new programming language requires variable names to start with a letter (upper or lowercase), which can be followed by lette
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Answer:

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Doubling this amount to account for both upper and lower case letters.

Therefore, Total characters (Upper + Lower Case) = 52 characters

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Underscore = 1 character

Thus, Total allowed characters = 52 + 10 + 1 = 63

This is a problem of the permutation as order of the characters results in a different name.

Our file name should be of atleast 3 and smaller than 7 (i.e. 6) characters

Therefore, total possible permutations can be obtained by subtraction permutation of 2 characters from the permutations of 6 characters.

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3 years ago
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A hockey puck slides across the ice with an initial velocity of 7.2 m/s. It has a deceleration of 1.1 m/s2 and is traveling towa
dezoksy [38]

Answer:

0.74 s

Explanation:

We can solve the problem by using the following SUVAT equation:

d = ut + \frac{1}{2}at^2

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u = 7.2 m/s is the initial velocity

a = -1.1 m/s^2 is the acceleration (which is negative since it is a deceleration)

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This is a second-order equation, whose solutions are given by:

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t = 0.74 s

t = 12.36 s

The solution we are looking for is the first one, because it corresponds to the first time at which the hockey puck has travelled the distance of 5.0 m, reaching the goal.

8 0
3 years ago
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