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2 years ago

If a car travels 216 kilometers in 4 hours, calculate its speed.

Physics

2 answers:

Mariana [72]2 years ago

6 0

Answer:

15 m/s

Explanation:

Speed(m/s) = distance(m)/time(s)

distance = 216 km = 216,000 m

time = 4 hours = 14,400 s

speed = 216000/14400 = 15 m/s

bekas [8.4K]2 years ago

6 0

Answer:

V=S/T

V=216km/4hr

V=54km/hr

Explanation:

1km/hr = 5/18 m/s

54km/hr= X

X=5/18m/s * 54km/hr

1km/hr

X=15m/s(approximately)

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GREYUIT [131]

Answer:

1066.67 m

Explanation:

Given:

v₀ = 96 km/h = 26.67 m/s

v = 48 km/h = 13.33 m/s

Δx = 800 m

Find: a

v² = v₀² + 2aΔx

(13.33 m/s)² = (26.67 m/s)² + 2a (800 m)

a = -0.333 m/s²

Given:

v₀ = 26.67 m/s

v = 0 m/s

a = -0.333 m/s²

Find: Δx

v² = v₀² + 2aΔx

(0 m/s)² = (26.67 m/s)² + 2 (-0.333 m/s²) Δx

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7 0

3 years ago

g (15 points) Picture taken from problem 13-35. A 2000 kg truck is traveling at 25 meters/second. The driver suddenly hits the b

otez555 [7]

Answer:

Δx = 3.99 m

Explanation:

To determine distance, use kinetic energy

will make it short and easy.

KE=1/2mv2 and KE=Δxmgμ

Set the equations equal to each other

1/2mv2=Δxmgμ (Note: The masses cancel )

1/2v2=Δxgμ Solve for Δx

where g=9.8

Δx=v2/(2gμ) Δx = 25 / (2 * 9.8 * 0.32) Δx = 3.99 m

Please let me know if its correct, if not report it so we can correct it.

6 0

4 years ago

Robert dropped his new iPhone from his balcony. It hit the ground 3.5 seconds later. What was the height of his balcony?

Lorico [155]

its B. 60 meters

Explanation:

cause I looked up a calculator and solved it

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3 years ago

The driver of a car traveling at 31.3 m/s applies the brakes and undergoes a constant deceleration of 1.6 m/s2.How many revoluti

lisov135 [29]

Answer:

$R=156.99\operatorname{Re}vs$

Explanation: The equations used are as follows:

$\begin{gathered} x(t)=x_o+v_ot+\frac{1}{2}at^2\Rightarrow(1) \\ v(t)=v_o+at\Rightarrow(2) \end{gathered}$

By using equation (2), the time needed for the car to come to rest is calculated as follows:

$\begin{gathered} v(t)=(31.3ms^{-1})_{}+(-1.6ms^{-2})t=0 \\ t=\frac{31.3ms^{-1}}{1.6ms^{-2}}=19.56s \\ t=19.563s \end{gathered}$

By using equation (1), The total distance traveled in that time would be as:

$\begin{gathered} x(19.563s)=_{}(31.3ms^{-1})\cdot(19.563s)+\frac{1}{2}(-1.6ms^{-2})\cdot(19.563s)^2\Rightarrow(1) \\ x(19.563s)=612.31-306.17=306.14m \\ \therefore\Rightarrow \\ x(19.563s)=306.14m \end{gathered}$

The revolutions taken by the tire before the car comes to rest would be:

$\begin{gathered} C=2\pi\cdot(0.31m)=1.95m \\ R=\frac{x(19.563s)}{C}=\frac{306.14m}{1.95m}=156.99\operatorname{Re}v \\ R=156.99\operatorname{Re}vs \end{gathered}$

3 0

2 years ago

Risks are only in a persons mind would know from facts to back them up

lyudmila [28]

Risks are only in a persons

8 0

4 years ago