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2 years ago

Amines are ________. brønsted-lowry bases brønsted-lowry acids neutral in water solution unreactive

Chemistry

1 answer:

sammy [17]2 years ago

8 0

Answer:

A.) Brønsted-Lowry bases

Explanation:

Amines have a lone pair of electrons.

Brønsted-Lowry bases donate a lone pair of electrons in exchange for a hydrogen ion.

Therefore, if exposed to an acid, amines will give up electrons in order to bond with a hydrogen. This makes them Brønsted-Lowry bases.

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The base unit of a measured liquid called volume is?

Dafna1 [17]

The answer you need is Volume.

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3 years ago

What are the steps for scientific method in order

Anna007 [38]

Make an observation.

Conduct research.

Form hypothesis.

Test hypothesis.

Record data.

Draw conclusion.

Replicate.

One thing that is designed to change in the set up of the experiment. ( The things that I can change) Independent Variable.

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3 years ago

If you know the poh of a solution how can you determine its ph

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POH+pH=14,
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3 years ago

If the half life of iridium-182 is 15 years, how much of a 3 gram sample is left after 2 half-lives?

padilas [110]

Answer:

D. 0.75 grams

Explanation:

The data given on the iridium 182 are;

The half life of the iridium 182, $t_{(1/2)}$ = 15 years

The mass of the sample of iridium, N₀ = 3 grams

The amount left, N(t) after two half lives is given as follows;

$N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}} }$

For two half lives, t = 2 × $t_{(1/2)}$

∴ t = 2 × 15 = 30

$\dfrac{t}{t_{(1/2)}} = \dfrac{30}{15} = 2$

$\therefore N(t) = 3 \times\left (\dfrac{1}{2} \right )^2 = 0.75$

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3 years ago

The ccl4 formed in the first step is used as a reactant in the second step. if 2.00 mol of ch4 reacts, what is the total amount

Leni [432]

<span>CH4 + 4 Cl2 â†’ CCl4 + 4 HCl (4.00 mol CH4) x (1/1) x (0.70) = 2.80 mol CCl4 (4.00 mol CH4) x (4/1) x (0.70) = 11.2 mol HCl CCl4 + 2 HF â†’ CCl2F2 + 2 HCl (2.80 mol CCl4) x (2/1) x (0.70) = 3.92 mol HCl 11.2 mol + 3.92 mol = 15.1 mol HCl from both steps</span>

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3 years ago