2CH3COOH +Na2CO3 ----> 2CH3COONa + H20 + CO2
know you can find what all products formed from his reaction
Answer:
44 g
Explanation:
The formula for the number of moles (n) is equal to
.
Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .
The molecular weight of
= 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol
We plug in the numbers in the derived formula for the mass and we get :
mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g
Hi Lara
The answer is : C
Is equal to
I hope that's help!
The average atomic mass of her sample is 114.54 amu
Let the 1st isotope be A
Let the 2nd isotope be B
From the question given above, the following data were obtained:
- Abundance of isotope A (A%) = 59.34%
- Mass of isotope A = 113.6459 amu
- Mass of isotope B = 115.8488 amu
- Abundance of isotope B (B%) = 100 – 59.34 = 40.66%
- Average atomic mass =?
The average atomic mass of the sample can be obtained as follow:

Thus, the average atomic mass of the sample is 114.54 amu
Learn more about isotope: brainly.com/question/25868336
Answer:
Lake and River pollution?
Explanation: