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KengaRu [80]
3 years ago
6

21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4

Chemistry
1 answer:
bija089 [108]3 years ago
5 0
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
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3 years ago
What is the relative mass of the electron?
DerKrebs [107]

Answer:

The relative mass of electron is 0.0005

Explanation:

Atoms are the fundamental unit of matter. Every thing in the universe that occupy space and have mass is called matter. we can say that every matter is composed of atoms. while the atom is composed of subatomic particles called electron proton and neutron.

Subatomic particles       Relative charge       Relative mass

Proton                                 +1                              1

Neutron                                0                             1

Electron                                -1                           0.0005

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol = e⁻

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It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

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8 0
3 years ago
What mass of potassium chloride, KCl, is produced when 12.6 g of oxygen, 02, is produced?
blagie [28]

Mass of KCl= 19.57 g

<h3>Further explanation</h3>

Given

12.6 g of Oxygen

Required

mass of KCl

Solution

Reaction

2KClO3 ⇒ 2KCl + 3O2

mol O2 :

= mass : MW

= 12.6 : 32 g/mol

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From the equation, mol KCl :

= 2/3 x mol O2

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Mass KCl :

= mol x MW

= 0.2625 x 74,5513 g/mol

= 19.57 g

4 0
2 years ago
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