Answer : The half-life of the compound is, 145 years.
Explanation :
First we have to calculate the rate constant.
Expression for rate law for first order kinetics is given by:
where,
k = rate constant = ?
t = time passed by the sample = 60.0 min
a = let initial amount of the reactant = 100 g
a - x = amount left after decay process = 100 - 25 = 75 g
Now put all the given values in above equation, we get
Now we have to calculate the half-life of the compound.
Therefore, the half-life of the compound is, 145 years.
The answer to this question would be:5 mol
To answer this question, you need to know the chemical equation of mg3(po4)2 when forming an ion. The equation should be: <span>mg3(po4)2= 3Mg(2+) +2PO4(3-)
That means for 1 mol of </span><span>mg3(po4)2 there will be 3 magnesium(cation) ion and 2 phosphates(anion) ion, the result would be 5 mol of ion.</span>
Answer:
80.7 L
Step-by-step explanation:
This looks like a case where we can use the Ideal Gas Law to calculate the volume.
pV = nRT Divide both sides by p
V = (nRT)/p
=====
Data:
n = 5.00 mol
R = 0.082 06 L·atm·K⁻¹mol⁻¹
T = (120 +273.15) K = 393.15K
p = 1520 mmHg × 1 atm/760 mmHg = 2.00 atm
=====
Calculation:
V = (5.00 × 0.082 06 × 393.15)/2.00
V = 161.3/2.00
V = 80.7 L
Answer:
Explanation:
There are key organs and system that assist in ensuring the body maintains homeostasis in the case of water-salt balance.
The excretory system: When one sweats, a lot of water content of the blood can drop (this is what causes the individual to be thirsty). In order to maintain a certain water-salt balance, the excretory system passes some salt out of the body in the form of urine (this is the reason the urine is usually yellowish but small in volume during the summer).
Endocrine system: When water content of the blood drops, vasopressin (also called antidiuretic hormone) is released into the bloodstream stimulating the kidneys to conserve water and release less urine (as said earlier). However, if the body is hydrated, less vasopressin is released and more water is passed in the urine.
The amount of heat required is 9.0 kJ.
<em>q = mC</em>Δ<em>T
</em>
Δ<em>T</em> = <em>T</em>_f – <em>T</em>_i = 65 °C – 32 °C = 33 °C
<em>q</em> = 65 g × 4.184 J·°C⁻¹g⁻¹ × 33 °C = 9000 J = 9.0 kJ
