Answer:
Hydrochloric acid reacts with the materials to produce bubbling, or fizzing, a gas, and heat.
Explanation:
Answer:
Explanation:
Hello,
In this case, for this heat transfer process in which the heat lost by the hot platinum is gained by the cold deuterium oxide based on the equation:
We can represent the heats in terms of mass, heat capacities and temperatures:
Thus, we solve for the mass of platinum:
Next, by using the density of platinum we compute the volume:
Which computed in terms of the edge length is:
Therefore, the edge length turns out:
![a=\sqrt[3]{180cm^3}\\ \\a=5.65cm](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B180cm%5E3%7D%5C%5C%20%5C%5Ca%3D5.65cm)
Best regards.
<h2>♨ANSWER♥</h2>
pl (25*C)
Arginine -----> 10.76
Glutamic -----> 3.08
Asparagine -----> 5.43
Tyrosine -----> 5.63
<u>☆</u><u>.</u><u>.</u><u>.</u><u>hope this helps</u><u>.</u><u>.</u><u>.</u><u>☆</u>
_♡_<em>mashi</em>_♡_
Answer:
Mass of Sodium = 574.75 g
Mass of Chlorine = 886.25 g
Explanation:
The balance chemical equation for the synthesis of NaCl is,
2 Na + Cl₂ → 2 NaCl
Step 1: <u>Find out moles of each reactant required,</u>
According to balance chemical equation,
2 moles of NaCl is produced by = 2 moles of Na
So,
25 moles of NaCl will be produced by = X moles of Na
Solving for X,
X = 25 mol × 2 mol / 2 mol
X = 25 moles of Na
Similarly for Cl₂,
According to balance chemical equation,
2 moles of NaCl is produced by = 1 mole of Cl₂
So,
25 moles of NaCl will be produced by = X moles of Cl₂
Solving for X,
X = 25 mol × 1 mol / 2 mol
X = 12.5 moles of Cl₂
Step 2: <u>Convert each moles to mass as;</u>
Mass = Moles × Atomic Mass
For Na,
Mass = 25 mol × 22.99 g/mol
Mass = 574.75 g
For Cl₂,
Mass = 12.5 mol × 70.90 g/mol
Mass = 886.25 g
Answer:
The order of the reaction with respect to the gas = 2
Explanation:
Let the original gas pressure be [G₀]
Initial rate of reaction is given as
r = k [G₀]ⁿ
When 10% had reacted, amount of gas left = [0.9G₀], r = 9.71 Pa/s
r = k [0.9G₀]ⁿ = 9.71 (eqn 1)
when 20% had reacted, amount of gas left = [0.8G₀], r = 7.67 Pa/s
r = k [0.8G₀]ⁿ = 7.67 (eqn 2)
Dividing (eqn 1) by (eqn 2)
(9.71/7.67) = [0.9/0.8]ⁿ
1.266 = 1.125ⁿ
1.125ⁿ = 1.266
Take natural logarithms of both sides
n (In 1.125) = In 1.266
n = 0.236/0.118
n = 2.
