Answer:
electrophile(H⁺) is needed to react with alkene in the first step and nucleophile (OH⁻) is not available in the first step
Explanation:
Answer:
the correct option is : If body fluids are too acidic, carbonic acid is excreted through the respiratory system in the form of carbon dioxide and water.
Explanation:
Metabolic acidosis is compensated by two systems, the renal and respiratory systems.
In the case of the respiratory system, the mechanism it uses to compensate for this phenomenon is to release the carbonic acid molecule dissociated into its components, that is, in the form of water and carbon dioxide.
The greater the acidosis, the more hyperventilation the person will have, and this is because they seek to eliminate carbonic acid more efficiently and quickly, along with renal excision.
The metabolic acidosis generated by carbonic acid is lethal, since the proteins in our body are denatured and the homeostasis of all systems is corrupted.
Answer:
Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.
Explanation:
- It is a stichiometry problem.
- We should write the balance equation of the mentioned chemical reaction:
<em>2Al + 3CuCl₂ → 3Cu + 2AlCl₃.</em>
- It is clear that 2.0 moles of Al foil reacts with 3.0 moles of CuCl₂ to produce 3.0 moles of Cu metal and 2.0 moles of AlCl₃.
- Also, we need to calculate the number of moles of the reported masses of Al foil (0.50 g) and CuCl₂ (0.75 g) using the relation:
<em>n = mass / molar mass</em>
- The no. of moles of Al foil = mass / atomic mass = (0.50 g) / (26.98 g/mol) = 0.0185 mol.
- The no. of moles of CuCl₂ = mass / molar mass = (0.75 g) / (134.45 g/mol) = 5.578 x 10⁻³ mol.
- <em>From the stichiometry Al foil reacts with CuCl₂ with a ratio of 2:3.</em>
∴ 3.85 x 10⁻³ mol of Al foil reacts completely with 5.578 x 10⁻³ mol of CuCl₂ with <em>(2:3)</em> ratio and CuCl₂ is the limiting reactant while Al foil is in excess.
- From the stichiometry 3.0 moles of CuCl₂ will produce the same no. of moles of copper metal (3.0 moles).
- So, this reaction will produce 5.578 x 10⁻³ mol of copper metal.
- Finally, we can calculate the mass of copper produced using:
mass of Cu = no. of moles x Atomic mass of Cu = (5.578 x 10⁻³ mol)(63.546 g/mol) = 0.354459 g ≅ 0.36 g.
- <u><em>So, the answer is:</em></u>
<em>Approximately 0.36 grams, because copper (II) chloride acts as a limiting reactant.</em>
Your answer would be, Gas atoms subjected to the electricity emit bright lines of light.
Hop that helps!!!
Complete Question:
The complete question is on the first uploaded image
Answer:
The solution is on the second uploaded image
Explanation:
The explanation of the above solution is on the third uploaded image.
