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solniwko [45]
2 years ago
9

True or

Chemistry
1 answer:
VashaNatasha [74]2 years ago
6 0

This statement is True. If the temperature of this system is increased, the concentration of carbon monoxide decreases.

The principle [a] dictates that we should raise the temperature at a constant volume in order to increase the concentration of CO2 because it is an endothermic reaction.

[b] Because there are equal numbers of reactions and products in the reaction, the condition of equilibrium cannot be affected by a change in volume.

[c] As reaction concentration rises, equilibrium moves in favor of the product and the concentration of the products, which results in an increase in CO2

learn more about carbon monoxide: brainly.com/question/18330533

#SPJ4

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Consider the fructose-1,6-bisphosphatase reaction. Calculate the free energy change if the ratio of the concentrations of the pr
Lyrx [107]

Answer:

The free energy change for the reaction at 37.0°C is -8.741 kJ.

Explanation:

The free energy of the reaction is given by :

\Delta G=\Delta G^o+RT\ln K

where,

\Delta G^o = standard Gibbs free energy

R = Gas constant = 8.314J/K mol

T = temperature in Kelvins

K = equilibrium constant

We have :

\Delta G^o=-16.7 kJ/mol=-16,700 J/mol

1 kJ = 1000 J

T = 37.0 C = 37 +273.15 K = 310.15 K

Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9

\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]

=-8,741.22 J = -8.741 kJ

The free energy change for the reaction at 37.0°C is -8.741 kJ.

5 0
3 years ago
Qual e o maior orgao do corpo humano
morpeh [17]
El órgano interno más grande es el hígado. Pero el órgano externo más grande es la piel, <span>Espero que esto ayudó!</span>
6 0
3 years ago
Why carbon monoxide is not acidic ​
mojhsa [17]

Answer:

Well, carbon monoxide can be created from formic acid by adding sulphuric acid which will dehydrate said formic acid:

HCOOH

−

→

−

−

−

H

2

SO

4

CO+H

2

O

HCOOH→HX2SOX4CO+HX2O

Therefore, we can imagine the reverse reaction theoretically, which would make carbon monoxide an acidic oxide. However, the forward reaction does not proceed easily and it needs both the high acidity of sulphuric acid and its strong dehydrative properties to actually work. And your question mentions using hot, concentrated sodium hydroxide to make the reverse one work.

Most oxides that are classified as acidic or basic either have a very electrophilic central atom (e.g.  

CO

2

COX2

) which can be attacked by the weak nucleophile water (which in turn can then release an acidic proton), or they have a high charge density on the oxygen which allows it to abstract a proton from water directly. Carbon monoxide is neither. If you check out its molecular orbitals, you will notice that even though carbon is partially positive it has the largest HOMO contribution, meaning a proton would be more likely to attatch to the carbon side — which doesn’t want one at all. The LUMO is, luckily, also more carbon-centred, meaning nucleophilic attacks on carbon are possible. However, it is also degenerate due to the double bond so that an attack is not favoured.

Thus, the carbon monoxide molecule is one that won’t react with water at all and totally defies the concept of acidic/basic oxides.

Abbreviations:

HOMO is a widely used abbreviation for the Highest Occupied Molecular Orbital, i.e. the one with the highest energy that still contains electrons. It is usually the orbital that will attack nucleophilicly or that will be attacked electrophilicly.

LUMO is a widely used abbreviation for the Lowest Unoccupied Molecular Orbital, i.e. the virtual (unoccupied) orbital that has the lowest energy. When considering a nucleophilic attack, the attacking electrons will usually interact with the LUMO. Electrophiles attack with other molecules’ HOMO with their LUMO.

Explanation:

7 0
3 years ago
If an object has a density of 0.55 g/mL, what is its density in cg/L?
expeople1 [14]

"cg" is centigram, which is one-hundredth of a gram.

I will first convert from g to cg (multiply by 100), then from mL to L (multiply by 1000).

\frac{0.55g}{mL}*\frac{100cg}{1g}*\frac{1000mL}{1L}=55,000\frac{cg}{L} \ or \ 5.5e4\frac{cg}{L}

3 0
4 years ago
What is the chemical name of NaCl₂
Elena L [17]

Answer:

It’s sodium chloride

Explanation:

Hope that helps

4 0
3 years ago
Read 2 more answers
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